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4 years ago

Explain why non ionic compounds are soluble in water ?

1 answer:

5 0

Water also dissolves non-ionic substances.This is because C2H5OH has a polar Oh and the bond that the water molecules like to hang around. Many substances do not dissolve in water and that is because they are non-polar and do not interact well with water molecules. A common example is oil and water.

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I will give you 100 points and mark you as brainilest if you answer the whole thing correctly.

Nookie1986 [14]

Answer:

1.) $Al_{2} O_{3}$

2.) $Li_{3} N\\$

3.) 2HCl

4.) MgO

5.) Mg and $O_{2}$

6.) $H_{2}$ and $O_{2}$

7.)Na and $Br_{2}$

8.) 3 aluminums and 3 chlorides

Explanation:

6 0

3 years ago

Samples of three different compounds were analyzed and the masses of each element were determined.

Dafna1 [17]

First, you have to convert mass to moles by making use of molecular weights [N = 14 g/mol and O = 16 g/mol)

A.
5.6/14 = 0.4 mol N
3.2/16 = 0.2 mol O
mol ratio = 2 mol N/1 mol O => N2O

B.
3.5/14 = 0.25 mol N
8.0/16 = 0.5 mol O
mol ratio = 1 mol N/2 mol O => NO2

C.
1.4/14 = 0.1 mol N
4.0/16 = 0.25 mol O
mol ratio = 2 mol N/5 mol O => N2O5

6 0

3 years ago

PLS HELPPP How many moles of oxygen atoms (not molecules) are present in 6.41×1025 molecules of dinitrogen pentoxide (N2O5)? 1.

olga55 [171]

Answer:

(4) 266 moles

Explanation:

We have Dinitrogen Pentoxide N2O5

6.41*10^25 molecules are given

No of Moles of N2O5 = $\frac{No of Molecules }{Avogadro's Number}$

= $\frac{6.41 * 10^25}{6.022*10^23}$

= 106.5 mol

Now using Unitary Method

2 Mole of Nitrogen pentoxide require 5 mole of Oxygen to form N2O5

1 mole of N = $\frac{5}{2}*O$

In 106.5 mole of N = $\frac{5}{2}*106.5$ = 266.25 mole

So, 6.41*10^25 molecules of N2O5 will require 266.25 mole of Oxygen atoms.

5 0

3 years ago

Balance the following chemical equation

ratelena [41]

Answer:

Explanation:

4). Ca(NO₃)₂ + Na₂SO₄ → CaSO₄ + 2Na(NO₃)₂

This question is incorrect.

Since, the final product by reacting Na⁺⁺ and NO₃⁻⁻ is NaNO₃

Correct equation will be,

Ca(NO₃)₂ + Na₂SO₄ → CaSO₄ + 2NaNO₃

This equation is in the balanced form.

5). Ni(NO₃)₂ + KI → NiI + 2K(NO₃)₂

Correct equation will be,

Ni(NO₃)₂ + KI → NiI₂ + 2KNO₃

[Since final product by reacting Ni⁺⁺ and I⁻ is NiI₂]

Balanced form of this equation will be,

Ni(NO₃)₂ + 2KI → NiI₂ + 2KNO₃

6). Ni(NO₃)₂ + KOH → NiOH + K(NO₃)₂

Correct form of the equation will be

Ni(NO₃)₂ + KOH → Ni(OH)₂ + KNO₃

[Since reaction of Ni⁺⁺ and OH⁻ gives Ni(OH)₂ and the reaction of K⁺ and NO₃⁻ gives KNO₃]

Now balancing this equation,

Ni(NO₃)₂ + KOH → Ni(OH)₂ + 2KNO₃

↓

Ni(NO₃)₂ + 2KOH → Ni(OH)₂ + 2KNO₃

8 0

4 years ago

The normal boiling point of ethanol (C2H5OH) is 78.3 oC and its molar enthalpy of vaporization is 38.56 kJ/mol. What is the chan

Sloan [31]

Answer:

The change in entropy in the system is -231.5 J/K

Explanation:

Step 1: Data given

The normal boiling point of ethanol (C2H5OH) is 78.3 °C = 351.45 K

The molar enthalpy of vaporization of ethanol is 38.56 kJ/mol = 38560 J/mol

Mass of ethanol = 97.2 grams

Pressure = 1 atm

Step 2: Calculate the entropy change of vaporization

The entropy change of vaporization = molar enthalpy of vaporization of ethanol / temperature

The entropy change of vaporization = 38560 J/mol / 351.45 K

The entropy change of vaporization = -109.72 J/k*mol

Step 3: Calculate moles of ethanol

Moles ethanol = mass / molar mass ethanol

Moles ethanol = 97.2 grams / 46.07 g/mol

Moles ethanol = 2.11 moles

Step 4: Calculate change in entropy

For 1 mol = -109.72 J/K*mol

For 2.11 moles = -231.5 J/K

The change in entropy in the system is -231.5 J/K

7 0

3 years ago