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4 years ago

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How might taxes have an impact on your financial plan? A. Taxes impact how high interest rates are. B. Taxes control how much of

your income you keep. C. Taxes don't apply to money you add to your financial reserve. D. Taxes control the rate of inflation.

2 answers:

Ratling [72]4 years ago

4 0

Answer:B. Taxes control how much of your income you keep.

Explanation:

Tax is the amount from income which get deducted as the amount used by the government. The government use tax for construction of roads and instructure.

The deduction of taxes from income will make the income a amount which can be used for financial planning.

amm18124 years ago

3 0

The answer would be : <span>B. Taxes control how much of your income you keep.

Hope this helps !
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If a satellite travels 62,000,000 miles from earth, how can we write it in scientific notation

Fudgin [204]

Answer:

6.2 x 10^6

Explanation:

The 6 at the end is an exponent the carrot is the symbol

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3 years ago

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The si unit for acceleration is blank

True [87]

Answer:

meters per second squared

Explanation:

Because acceleration is equal to velocity over time where velocity is meters per second and time is measured in seconds making acceleration ms-2

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3 years ago

The capacitor is now disconnected from the battery, and the dielectric plate is slowly removed the rest of the way out of the ca

Xelga [282]

The question is incomplete. The complete question is :

A dielectric-filled parallel-plate capacitor has plate area A = 10.0 cm2 , plate separation d = 10.0 mm and dielectric constant k = 3.00. The capacitor is connected to a battery that creates a constant voltage V = 15.0 V . Throughout the problem, use ϵ0 = 8.85×10−12 C2/N⋅m2 .

Find the energy U1 of the dielectric-filled capacitor. I got U1=2.99*10^-10 J which I know is correct. Now I need these:

1. The dielectric plate is now slowly pulled out of the capacitor, which remains connected to the battery. Find the energy U2 of the capacitor at the moment when the capacitor is half-filled with the dielectric.

2. The capacitor is now disconnected from the battery, and the dielectric plate is slowly removed the rest of the way out of the capacitor. Find the new energy of the capacitor, U3.

Solution :

Given :

$A = 10 \ cm^2$

$=0.0010 \ m^2$

d = 10 mm

= 0.010 m

Then, Capacitance,

$C=\frac{k \epsilon_0 A}{d}$

$C=\frac{8.85 \times 10^{12} \times 3 \times 0.0010}{0.010}$

$C=2.655 \times 10^{12} \ F$

$U_1 = \frac{1}{2}CV^2$

$U_1 = \frac{1}{2} \times 2.655 \times 10^{-12} \times (15V)^2$

$U_1=2.987 \times 10^{-10}\ J$

Now,

$C_k=\frac{1}{2} \frac{k \epsilon_0}{d} \times \frac{A}{2}$

And

$C_{air}=\frac{1}{2} \frac{\epsilon_0}{d} \times \frac{A}{2}$

In parallel combination,

$C_{eq}= C_k + C_{air}$

$C_{eq} = \frac{1}{2} \frac{\epsilon_0 A}{d}(1+k)$

$C_{eq} = \frac{1}{2} \times \frac{8.85 \times 10^{-12} \times 0.0010}{0.01} \times (1+3)$

$C_{eq} = 1.77 \times 10^{-12}\ F$

Then energy,

$U_2 =\frac{1}{2} C_{eq} V^2$

$U_2=\frac{1}{2} \times 1.77 \times 10^{-12} \times (15V)^2$

$U_2=1.99 \times 10^{-10} \ J$

b). Now the charge on the $\text{capacitor}$ is :

$Q=C_{eq} V$

$Q = 1.77 \times 10^{-12} \times 15 V$

$Q = 26.55 \times 10^{-12} \ C$

Now when the capacitor gets disconnected from battery and the $\text{dielectric}$ is slowly $\text{removed the rest}$ of the way out of the $\text{capacitor}$ is :

$C_3=\frac{A \epsilon_0}{d}$

$C_3 = \frac{0.0010 \times 8.85 \times 10^{-12}}{0.01}$

$C_3=0.885 \times 10^{-12} \ F$

$C_3 = 0.885 \times 10^{-12} \ F$

Without the dielectric,

$U_3=\frac{1}{2} \frac{Q^2}{C}$

$U_3=\frac{1}{2} \times \frac{(25.55 \times 10^{-12})^2}{0.885 \times 10^{-12}}$

$U_3=3.98 \times 10^{-10} \ J$

4 0

3 years ago

A 3.0 X 10^3 grams rock swings in a circle with a diameter of 1000 cm. Given the constant speed around the circle is 17.90 mph (

marissa [1.9K]

Answer:

a = 12.8 m/s^2

Explanation:

To find the centripetal acceleration you use the following formula:

$a_c=\frac{v^2}{r}$ (1)

v: tangential speed of the rock = 17.90mph

r: radius of the orbit = 1000cm/2 = 500cm = 0.5m

You first change the units of the tangential velocity in order to replace the values of v and r in the equation (1):

$17.90mph*\frac{1609.34m}{1\ m}*\frac{1\ h}{3600\ s}=8m/s$

Then, you use the equation (1):

$a_c=\frac{(8m/s)^2}{5m}=12.8\frac{m}{s^2}$

hence, the centripetal acceleration is 12.8 m/s^2

3 0

3 years ago

4. A rocket entering Mars' atmosphere can accelerate at -20.0 m/s2. If the rocket is originally going 1600 m/s

Feliz [49]

Answer:

v = 1400 m/s

Explanation:

Acceleration of the rocket, a = -20 m/s²

Initial speed of the rocket, u = 1600 m/s

Time, t = 10 s

We need to find the final velocity of the rocket. We can use first equation of motion to find it.

v = u+at

Put all the values,

v = 1600+(-20) (10)

= 1600-200

= 1400 m/s

So, the final velocity of the rocket is 1400 m/s.

3 0

3 years ago