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3 years ago

Which equation is used to help form the combined gas law?

Chemistry

1 answer:

kkurt [141]3 years ago

5 0

Answer:

The ideal gas equation

Explanation:

The ideal gas equation is derived from the combination of three gas laws:

Boyle's law
Charles's law
Avogadro's law.

The ideal gas law is expressed mathematically as: PV=nRT where:

P is pressure

V is volume

n is the number of moles

R is the ideal gas law

T is temperature.

To obtain the combined gas law, we assume that n=1 and this gives:

$\frac{PV}{T}$ = R

Therefore:

$\frac{P_{1} V_{1} }{T_{1} }$ = $\frac{P_{2} V_{2} }{T_{2} }$

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3 years ago

635 mL of a gas is at a pressure of 8.00 atm. What is the volume of the gas at standard pressure (STP)?

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The new volume at standard temperature and pressure is 5.08 L.

Explanation:

As per the kinetic theory of gases, the volume occupied by gas molecules will be inversely proportional to the pressure of the gas molecules. This is termed as Boyle's law.

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Thus, if two pressure and two volumes are given then,

$P_{1} V_{1} = P_{2} V_{2}\\$

Now, we known the values of P₁ = 8 atm, V₁ = 635 mL, P₂ = 1 atm and V₂ we have to determine. We are considering P₂ = 1 atm, because we have to determine V₂ at standard temperature and pressure. And standard pressure is 1 atm.

$8*635*10^{-3} = 1 *V{2} \\\\V_{2} = \frac{8*635*10^{-3} }{1} = 5.08 L$

Thus, the new volume at standard temperature and pressure is 5.08 L.

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3 years ago

Determine the number of atoms of each element in the empirical formula of a compound with the following composition:

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To determine the empirical formula of the compound, we assume a basis of 100 g of this compound. We calculate as follows:

C = 68.75 g
H = 10.90 g
O = 20.35 g

We convert these mass to moles,
C = 68.75 g / 12.01 g/mol = 5.72 mol
H = 10.90 g / 1.01 g/mol = 10.79 mol
O = 20.35 g / 16 g/mol = 1.27 mol

C = 5.72 mol / 1.27 mol = 5
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