Ask question

Ask question

All categories

3 years ago

5

Which equation is used to help form the combined gas law?

1 answer:

kkurt [141]3 years ago

5 0

Answer:

The ideal gas equation

Explanation:

The ideal gas equation is derived from the combination of three gas laws:

Boyle's law
Charles's law
Avogadro's law.

The ideal gas law is expressed mathematically as: PV=nRT where:

P is pressure

V is volume

n is the number of moles

R is the ideal gas law

T is temperature.

To obtain the combined gas law, we assume that n=1 and this gives:

$\frac{PV}{T}$ = R

Therefore:

$\frac{P_{1} V_{1} }{T_{1} }$ = $\frac{P_{2} V_{2} }{T_{2} }$

You might be interested in

A gas occupies 525 mL at a pressure of 45.0 kPa. What would the volume of the gas be at a pressure of 65.0 kPa

choli [55]

Answer:

The volume of the gas at a pressure of 65.0 kPa would be 363 mL

Explanation:

Boyle's Law is a gas law that relates the pressure and volume of a certain amount of gas, without temperature variation, that is, at constant temperature.

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. In other words, the product P · V remains constant at the same temperature:

P*V=k

Being P1 and V1 the pressure and volume in state 1 and P2 and V2 the pressure and volume in state 2 are fulfilled:

P1*V1=P2*V2

In this case:

P1= 45 kPa= 45,000 Pa (being 1 kPa=1,000 Pa)
V1= 525 mL= 0.525 L (being 1 L=1,000 mL)
P2= 65 kPa= 65,000 Pa
V2= ?

Replacing:

45,000 Pa* 0.525 L= 65,000 Pa*V2

Solving:

$V2=\frac{45,000 Pa* 0.525 L}{65,000 Pa}$

V2=0.363 L=363 mL

<u><em>The volume of the gas at a pressure of 65.0 kPa would be 363 mL</em></u>

6 0

3 years ago

how many molecules of sulfuric acid are in a spherical raindrop of diameter 6.0 mm if the acid rain has a concentration of 4.4 *

Vitek1552 [10]

Answer:

The number of moles =

$Moles=4.97\times 10^{-8}$

The number of molecules =

$Molecules = 2.99\times 10^{16}$

Explanation:

Volume of the sphere is given by :

$V=\frac{4}{3}\pi r^{3}$

here, r = radius of the sphere

$radius=\frac{diameter}{2}$

$radius=\frac{6.0}{2}$

Radius = 3 mm

r = 3 mm

1 mm = 0.01 dm (1 millimeter = 0.001 decimeter)

3 mm = 3 x 0.01 dm = 0.03 dm

r = 0.03 dm

<em>("volume must be in dm^3 , this is the reason radius is changed into dm"</em>

<em>"this is done because 1 dm^3 = 1 liter and concentration is always measured in liters")</em>

$V=\frac{4}{3}\pi 0.03^{3}$

$V=\frac{4}{3}\pi 2.7\times 10^{-5}$

$V=1.13\times 10^{-4}dm^{3}$

$V=1.13\times 10^{-4}L$ (1 L = 1 dm3)

Now, concentration "C"=

$C=4.4\times 10^{-4}moles/liter$

The concentration is given by the formula :

$C=\frac{moles}{Volume(L)}$

This is also written as,

$Moles = C\times Volume$

$Moles=1.13\times 10^{-4}\times 4.4\times 10^{-4}$

$Moles=4.97\times 10^{-8}$ moles

One mole of the substance contain "Na"(= Avogadro number of molecules)

So, "n" mole of substance contain =( n x Na )

$N_{a}=6.022\times 10^{23}$

Molecules =

$Molecule=4.97\times 10^{-8}\times 6.022\times 10^{23}$

$Molecules = 2.99\times 10^{16}$ molecules

7 0

3 years ago

What is the molarity of a solution containing 56 grams of solute in 959 ml of solution? (molar mass of solute = 26 g/mol)?

jolli1 [7]

26g --- 1 mol
56g --- X
X= 56/26 = 2,154 mol

959 ml = 959cm³ = 0,959dm³

C = n/V
C = 2,154/0,959
C = 2,246 mol/dm³

8 0

3 years ago

Read 2 more answers

In the reaction, HCl + NaOH NaCl + H₂O, what is/are the reactant(s)?

Masja [62]

Answer:

HCI and NaOH

6 0

3 years ago

What technique would you use to separate alcohol from water?<br><br> please help!!!!!

krok68 [10]

Answer:

fractional distillation.

Explanation:

7 0

3 years ago

Read 2 more answers