Question

What is the molarity of a solution containing 56 grams of solute in 959 ml of solution? (molar mass of solute = 26 g/mol)?

Answer 1

26g --- 1 mol
56g --- X
X= 56/26 = 2,154 mol

959 ml = 959cm³ = 0,959dm³

C = n/V
C = 2,154/0,959
C = 2,246 mol/dm³

Answer 2

Answer: Molarity of solution will be 2.24 M.

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= moles of solute  

$V_s$ = volume of solution in ml = 959 ml

moles of solute =$\frac{\text {given mass}}{\text {molar mass}}=\frac{56g}{26g/mol}=2.15moles$

Now put all the given values in the formula of molarity, we get

$Molarity=\frac{2.15moles\times 1000}{959ml}=2.24mole/L$

Therefore, the molarity of solution will be 2.24 M.