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WINSTONCH [101]
3 years ago
13

What is the molarity of a solution containing 56 grams of solute in 959 ml of solution? (molar mass of solute = 26 g/mol)?

Chemistry
2 answers:
jolli1 [7]3 years ago
8 0
26g --- 1 mol
56g --- X
X= 56/26 = 2,154 mol

959 ml = 959cm³ = 0,959dm³

C = n/V
C = 2,154/0,959
C = 2,246 mol/dm³
Zepler [3.9K]3 years ago
5 0

Answer: Molarity of solution will be 2.24 M.

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute  

V_s = volume of solution in ml = 959 ml

moles of solute =\frac{\text {given mass}}{\text {molar mass}}=\frac{56g}{26g/mol}=2.15moles

Now put all the given values in the formula of molarity, we get

Molarity=\frac{2.15moles\times 1000}{959ml}=2.24mole/L

Therefore, the molarity of solution will be 2.24 M.

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Consider the reaction given below.
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Answer:

  • <u>K =  0.167 s⁻¹</u>

Explanation:

<u>1) Rate law, at a given temperature:</u>

  • Since all the data are obtained at the same temperature, the equilibrium constant is the same.

  • Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

        r = K [A]ᵃ [B]ᵇ

<u>2) Use the data from the table</u>

  • Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

         Divide r₂ by r₁:     [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

  • Use the first and second set of data to find the exponent a:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

        Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

                                  2ᵃ = 2 ⇒ a = 1

         

<u>3) Write the rate law</u>

  • r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

<u>4) Use any set of data to find K</u>

With the first set of data

  • r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K =  0.167 s⁻¹

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