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garik1379 [7]
3 years ago
11

How do you calculate the density of a gas, based on its temperature and pressure?

Chemistry
1 answer:
stiks02 [169]3 years ago
5 0
We can rearrange the ideal gas equation:
PV = nRT, where n is the number of moles equivalent to:
n = mass / Mr
PV = mRT/Mr
m/V = PMr/RT
density = PMr / RT; where Mr and R are constant.
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How many orbitals surround the nucleus in a neutral atom of sulfur (S)?
Leto [7]
<h2>C</h2>

Explanation:

The atomic number of S is 16

So,number of electrons in S is 16

The electronic configuration of S is 2,8,6

The orbital electronic configuration of S is ^{1}s_{2}^\text{ }^{2}s_{2}^\text{ }^{2}p_{x2}^\text{ }^{2}p_{y2}^\text{ }^{2}p_{z2}^\text{ }^{3}s_{2}^\text{ }^{3}p_{x2}^\text{ }^{3}p_{y1}^\text{ }^{3}p_{z1}^\text{ }

So,the number of orbitals involved is 9.

3 0
3 years ago
A student has a salt water solution. When the student adds more salt to the solution it completely dissolves. What type of solut
AlladinOne [14]

Answer:

<h2>Saturated</h2>

Explanation:

<em>A</em><em>saturated solution is a solution that contains the maximum amount of solute that is capable of being dissolved. Table salt (NaCl) readily dissolves in water.</em>

3 0
2 years ago
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When 500 g of water is cooled from 80.0°C to 10.0°C, how much heat energy is lost?
vampirchik [111]

I don’t know

Explanation:

6 0
3 years ago
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What does the answer of element 3Na2S2O3?
Fynjy0 [20]

Answer:

Explanation:

3× 22+2×32+ 6×16=

66+64+96=236

4 0
2 years ago
You dissolve 8.65 grams of lead(l) nitrate in water and then you add 2 50 grams of aluminum. This reaction occurs 2AI(S)+ 3Pb(NO
olga55 [171]

<u>Answer:</u> The theoretical yield of solid lead comes out to be 5.408 grams.

<u>Explanation:</u>

To calculate the moles, we use the following equation:  

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}  

  • <u>Moles of Lead nitrate:</u>

Given mass of lead nitrate = 8.65 grams

Molar mass of lead nitrate = 331.2 g/mol

Putting values in above equation, we get:

\text{Number of moles}=\frac{8.65g}{331.2g/mol}=0.0261moles

  • <u>Moles of Aluminium:</u>

Given mass of aluminium = 2.5 grams

Molar mass of aluminium = 27 g/mol

Putting values in above equation, we get:

\text{Number of moles}=\frac{2.5g}{27g/mol}=0.0925moles

For the given chemical reaction, the equation follows:

2AI(s)+3Pb(NO_3)_2(aq.)\rightarrow 3Pb(s)+2AI(NO3)_3(aq.

By Stoichiometry:

3 moles of lead nitrate reacts with 2 moles of aluminium

So, 0.0261 moles of lead nitrate are produced by = \frac{2}{3}\times 0.0261=0.0174moles of aluminium.

As, the required amount of aluminium is less than the given amount. Hence, it is considered as the excess reagent.

Lead nitrate is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

3 moles of lead nitrate are produces 3 moles of lead metal.

So, 0.0261 moles of lead nitrate will produce = \frac{3}{3}\times 0.0261=0.0261moles of lead metal.

  • Now, to calculate the grams or theoretical yield of lead metal, we put in the mole's equation, we get:

Molar mass of lead = 207.2 g/mol

Putting values in above equation, we get:

0.0261mol=\frac{\text{Given mass}}{207.2g/mol}

Mass of lead = 5.408 grams

Hence, the theoretical yield of solid lead comes out to be 5.408 grams.

8 0
3 years ago
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