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shutvik [7]
3 years ago
14

How many L of 3.0 M H2SO4 solution can be prepared by using 100.0 mL OF 18 M H2SO4?

Chemistry
1 answer:
AfilCa [17]3 years ago
8 0

Answer:

0.6 L

Explanation:

As this problem deals with a <em>dilution process</em>, we can solve it by using the following formula:

  • C₁V₁=C₂V₂

Where subscript 1 stands for the initial concentration and volume, while 2 stands for the diluted solution's. That means that in this case:

  • C₁ = 18 M
  • V₁ = 100 mL
  • C₂ = 3.0 M
  • V₂ = ?

We <u>input the data</u>:

  • 18 M * 100 mL = 3.0 M * V₂

And <u>solve for V₂</u>:

  • V₂ = 600 mL

Finally we <u>convert 600 mL to L</u>:

  • 600 mL / 1000 = 0.6 L
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a)

D = 0.79 g/cm³           m = 85.1 g

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