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shutvik [7]
3 years ago
14

How many L of 3.0 M H2SO4 solution can be prepared by using 100.0 mL OF 18 M H2SO4?

Chemistry
1 answer:
AfilCa [17]3 years ago
8 0

Answer:

0.6 L

Explanation:

As this problem deals with a <em>dilution process</em>, we can solve it by using the following formula:

  • C₁V₁=C₂V₂

Where subscript 1 stands for the initial concentration and volume, while 2 stands for the diluted solution's. That means that in this case:

  • C₁ = 18 M
  • V₁ = 100 mL
  • C₂ = 3.0 M
  • V₂ = ?

We <u>input the data</u>:

  • 18 M * 100 mL = 3.0 M * V₂

And <u>solve for V₂</u>:

  • V₂ = 600 mL

Finally we <u>convert 600 mL to L</u>:

  • 600 mL / 1000 = 0.6 L
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While conducting a lab experiment, Ali calculated that 1.20 E6 Joules of heat were needed to melt 18.5 kilograms of an unknown s
nordsb [41]

Answer:

Latent heat of fusion of the substance is 6.49\times 10^{4}J/kg

Explanation:

Latent heat of fusion denotes amount of energy (heat) per unit mass required to melt a solid material at constant temperature and pressure i.e. at it's melting point

Here amount of heat required = 1.20\times 10^{6}J

Mass of unknown substance being melted = 18.5 kg

So, latent heat of fusion of the substance = (required heat energy to melt)/(mass of the unknown substance) = \frac{1.20\times 10^{6}}{18.5}J/kg=6.49\times 10^{4}J/kg

So, latent heat of fusion of the substance is 6.49\times 10^{4}J/kg

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Explanation:

Hope this helped. Goodluck! xD

7 0
3 years ago
Read 2 more answers
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4 0
2 years ago
If the mole fraction of sulfuric acid H2SO4 is 0.432 what is the percent by mass of H2SO4.
Sever21 [200]

Answer:

19.47%

Explanation:

<em>The percentage by mass of </em>H_2SO_4<em> would be </em><em>19.47%</em><em>.</em>

The percentage by mass of a substance in solution is calculated as:

   \frac{mass of substance}{mass of substance + water}  * 100%

Given that the mole fraction of H_2SO_4 = 0.432

The total number of mole fraction of a solution = 1

Hence, mole fraction of water = 1 - 0.432 = 0.568

Mass of water = molar mass x mole

                              = 98.079 x 0.432 = 42.37 g

Mass of H_2SO_4 = molar mass x mole

                          = 18.02 x 0.568 = 10.24 g

Hence,

<em>%mass of</em> H_2SO_4 = \frac{10.24}{10.24 + 42.37} * 100

                         = 19.47%

4 0
3 years ago
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