<span>The answer is the H2CO. It has two sigma bonds ( the single bonds between each H and C) plus one pi bond and one sigma bond that consitute the double bond between C and O. The other compounds, CHCl3, H2S and HBr, only have single bonds which are sigma bonds.</span>
1)
a)
D = 0.79 g/cm³ m = 85.1 g
D = m / V
0.79 = 85.1 / V
V = 85.1 / 0.79 => 107.72 cm³
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b) D = m / V
0.79 = m / 125
m = 0.79 x 125 => 98.75 g
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hope this helps!
Answer:
d = 43.5 g/cm³
Explanation:
Given data:
Mass of magnesium cube = 217.501 g
Volume of magnesium cube = 5.00 cm³
Density of magnesium cube = ?
Solution:
Formula:
d = m/v
d = density
m = mass
v = volume
by putting values,
d = 217.501 g/ 5.00 cm³
d = 43.5 g/cm³
Answer:
potassium
The third alkali metal is K (potassium). The atomic number of K (potassium) is 19. Thus, the atomic number of third alkali metal is 19
Explanation: