1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
shutvik [7]
3 years ago
14

How many L of 3.0 M H2SO4 solution can be prepared by using 100.0 mL OF 18 M H2SO4?

Chemistry
1 answer:
AfilCa [17]3 years ago
8 0

Answer:

0.6 L

Explanation:

As this problem deals with a <em>dilution process</em>, we can solve it by using the following formula:

  • C₁V₁=C₂V₂

Where subscript 1 stands for the initial concentration and volume, while 2 stands for the diluted solution's. That means that in this case:

  • C₁ = 18 M
  • V₁ = 100 mL
  • C₂ = 3.0 M
  • V₂ = ?

We <u>input the data</u>:

  • 18 M * 100 mL = 3.0 M * V₂

And <u>solve for V₂</u>:

  • V₂ = 600 mL

Finally we <u>convert 600 mL to L</u>:

  • 600 mL / 1000 = 0.6 L
You might be interested in
Describe the relationship between predator and prey in a balanced ecosystem. Please hellppp.
Umnica [9.8K]

Answer:without predators, to keep prey from producing too many and over eating, the ecosystem suffers as there isn’t enough for the prey themselves to eat.

Explanation:

3 0
3 years ago
What name should be used for the ionic compound Cu(NO3)2
Sergeu [11.5K]
<span>Copper(II) nitrate. Hope i cleared your doubt</span>
6 0
2 years ago
Read 2 more answers
HELP!!!!!
faltersainse [42]

Answer:

5.17.

Explanation:

<em>∵ [H₃O⁺][OH⁻] = 10⁻¹⁴. </em>

[OH⁻] = 1.5  x 10⁻⁹ M.

∴ [H₃O⁺] = 10⁻¹⁴/[OH⁻] = 10⁻¹⁴/(1.5  x 10⁻⁹ M) = 6.66 × 10⁻⁶ M.

∵ pH = - log[H₃O⁺]

<em>∴ pH = - log(6.66 × 10⁻⁶ M) = 5.17. </em>

5 0
3 years ago
Read 2 more answers
If an experiment with 10.2 g barium chloride produced 14.5 g silver chloride, calculate thr experimental mole ratio of silver ch
Leni [432]
The  experimental  mole ratio  of silver chloride  to  barium chloride  is calculated as below

fin the mole of each compound

mole= mass/molar  mass
moles of AgCl = 14.5g/142.5 g/mol = 0.102  moles of AgCl
moles of BaCl2 = 10.2 g/208 g/mol =  0.049  moles of BaCl2

find the  mole ratio  by dividing each mole with the smallest  mole(0.049)

AgCl= 0.102/0.049 =2
BaCl2 = 0.049/0.049 =1
therefore  the mole   ratio   AgCl to  BaCl2  is  2 :1
3 0
3 years ago
Read 2 more answers
In a chemical equation
djverab [1.8K]

Answer:

Answer in explanation

Explanation:

A. This is wrong. The reactants are on the left side of the yields arrow

B. This is wrong. They can only be at one side at a time. They cannot be on both sides at the same time.

C. The products are on the right side of the yields arrow and not at the left side

D. This is correct. The reactants are on the left side of the yields arrow.

E. This is correct. We can have varying numbers of the number of atoms on both side of the yields arrow. The numbers may differ until we decide to balance the equation

4 0
3 years ago
Other questions:
  • 1.88gof potassium chloride is dissolved in300.mLof a23.0mMaqueous solution of silver nitrate.Calculate the final molarity of chl
    7·1 answer
  • OK SO HERES HOW ITS GONNA GO. IMA ASK YOU GUYS ONE MORE TIME BC THIS IS LIKE THE 3RD TIME IVE WAISTED MY POINTS IN THE SAME QUES
    13·1 answer
  • Why are the testicles outside the body instead of inside?
    6·1 answer
  • Two forces are described below: Force 1: The force with which Earth pulls a person to its center Force 2: The pulling force appl
    8·2 answers
  • A change of state does not affect an object's what?
    14·1 answer
  • Use the drop-down menus to complete each statement.
    9·1 answer
  • Someone help me please i’ll give brainly
    5·2 answers
  • The solubility of sugar in water is about 5g/ml. This means tha
    9·1 answer
  • Energy from the sun is absorbed by ____
    9·1 answer
  • How many significant figures does 7,874.9640 s have?<br> Submit Question
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!