The awnser would be True. Hope I helped!
Answer:
a)
b)
c)
d)
m
e)λ=∞
Explanation:
De Broglie discovered that an electron or other mass particles can have a wavelength associated, and that wavelength (λ) is:

with h the Plank's constant (
) and P the momentum of the object that is mass (m) times velocity (v).
a)

b)

c)

d)
m
e) 
λ=∞
It confirmed medeleeve's hypothesis (prediction) and showed the use of his table
The units are not consistent - 1 m/s is not the same as 1 km/h.
First thing to do would be to convert from one unit of speed to the other, say km/h to m/s. There are 1000 meters (m) for every kilometer (km) and 3600 seconds (s) for every hour (h), so

So in fact 1 km/h is about 4 times slower than 1 m/s.