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Deffense [45]
3 years ago
7

Two physical pendulums (not simple pendulums) are made from meter sticks that are suspended from the ceiling at one end. The sti

cks are uniform and are identical in all respects, except that one is made of wood (mass = 0.16 kg) and the other of metal (mass = 0.88 kg). They are set into oscillation and execute simple harmonic motion. Determine the period of (a) the wood pendulum and (b) the metal pendulum.
(A) T = ? s
(B) T = ? s
Physics
1 answer:
boyakko [2]3 years ago
3 0

Answer: A and B is 1.64 seconds.

The period is the same for the wood and metal pendulums because the mass has been eliminated mathematically in the expression for T.

Explanation: The period T is given by

T = 2π/ω, where ω is the angular frequency.

ω, angular frequency, is represented by

Sqaureroot of (m*g*L/I), where m is mass, L is the distance from pivot to the center of mass and I is the moment of inertia about the pivot .

Therefore

T = 2π/ sqaureroot(m*g*L/I),

Further expressed as

T = 2π*sqaureroot(I/m*g*L),

Inertia Is given by

I=1/3mL^2 where L=length of the stick. Since the meter stick is uniform, the distance L from one end to the center of mass is Upper L = one-half Upper L 0 period.

Thus the period of oscillation is expressed as;

T=2π*sqrt(I/mg(1/2L)

=2π*sqrt(1/3m*L^2/mg(1/2L)

= 2π*sqrt(2L/3g)

=2π*sqrt(2*1/3*9.8)

= 1.64 seconds

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kakasveta [241]

Answer:

W = 600 J

Explanation:

We have,

According to attached figure,

Height of the inclined plane is 60 m

Force acting on the block is 10 N

It is required to find the work must be done against gravity to move it to the top of the incline. The work done is given by :

W = mgh

or

W=F\times h\\\\W=10\times 60\\\\W=600\ J

So, the work done against the gravity is 600 J.

3 0
3 years ago
At exactly 3:14PM, the velocity of a dog running in a park points toward a group of flowers. Which of the following best describ
dmitriy555 [2]

Answer:

Options A, B, and C are all possible.

Explanation:

We know that the instantaneous velocity of the dog at 3:14PM is possitive to toward the flowers. But what about the acceleration to toward the flowers?

If the dog is decreasing speed at 3:14PM, it means that acceleration is negative toward the flowers, hence (since F=ma) the net force points away from the flowers.

If the dog is increasing speed at 3:14PM, it means that acceleration is positive toward the flowers, hence (since F=ma) the net force points toward the flowers.

If the dog is not increasing nor decreasing speed at 3:14PM, it means that acceleration is 0, hence (since F=ma) the net force is null and it does not point neighter to toward the flowers  nor away from the flowers. This happens when the forces acting on the dog are equal to both sides.

4 0
3 years ago
a 20 ft shipping container on a cargo ship has a mass of 24000 kg and a volume of 33.2m3. what is the density of the shipping co
Ira Lisetskai [31]

Answer:

722.89

Explanation:

mass=24000kg

volume=33•2

density=?

now,

density=mass/volume

=24000/33•2

=722•89

density=722•89 kg/m^3

3 0
3 years ago
Sully uses a battery and a coil of wire to create an electromagnet. Using the same materials, if he wants to increase the streng
garik1379 [7]
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The strength of magnetic field of such magnet is given with this equation:
B=\frac{NI\mu}{L}
Where N is the number of loops in the coil, I is the strength of the current flowing through the coil, L is the length of the coil, and \mu is <span>permeability of the electromagnet core material.
From this equation, we can see that increasing both the current and number of loops will increase the strength of the magnet.
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5 0
3 years ago
Consider the nearly circular orbit of Earth around the Sun as seen by a distant observer standing in the plane of the orbit. Wha
ikadub [295]

We have that the spring constant is mathematically given as

k=2.37*10^{11}N/m

Generally, the equation for angular velocity is mathematically given by

\omega=\sqrt{k}{m}

Where

k=spring constant

And

\omega =\frac{2\pi}{T}

Therefore

\frac{2\pi}{T}=\sqrt{k}{n}

Hence giving spring constant k

k=m((\frac{2 \pi}{T})^2

Generally

Mass of earth m=5.97*10^{24}

Period for on complete resolution of Earth around the Sun

T=365 days

T=365*24*3600

Therefore

k=(5.97*10^{24})((\frac{2 \pi}{365*24*3600})^2

k=2.37*10^{11}N/m

In conclusion

The effective spring constant of this simple harmonic motion is

k=2.37*10^{11}N/m

For more information on this visit

brainly.com/question/14159361

8 0
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