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PtichkaEL [24]
2 years ago
9

a serving of a particular fruit dessert contains 20.0 g of sugar. if all the sugar is sucrose, c12h22o11, how many molecules of

sugar are present in this serving?
Chemistry
1 answer:
Harrizon [31]2 years ago
6 0

Taking into account the definition of Avogadro's number and molar mass, 3.49334×10²² molecules of sucrose are present.

<h3>Definition of molar mass</h3>

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

<h3>Avogadro's Number</h3>

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

<h3>Molecules of sugar in this case</h3>

In first place, the molar mass of sucrose is 342 g/mole. So, you can apply the following rule of three: If by definition of molar mass 342 grams of the compound are contained in 1 mole, 20 grams of the compound are contained in how many moles?

amount of moles=\frac{20 gramsx1 mole}{342 grams}

<u><em>amount of moles= 0.058 moles</em></u>

Now, considering the Avogadro's number, you can apply the following rule of three: If 1 mole of the compound contains 6.023×10²³ molecules, 0.058 moles contains how many molecules?

amount of moleculas= (6.023×10²³ molecules × 0.058 moles)÷ 1 mole

<u><em>amount of molecules= 3.49334×10²² molecules</em></u>

Finally, 3.49334×10²² molecules of sucrose are present.

Learn more about

molar mass:

brainly.com/question/5216907

brainly.com/question/11209783

brainly.com/question/7132033

brainly.com/question/17249726

Avogadro's Number:

brainly.com/question/11907018

brainly.com/question/1445383

brainly.com/question/1528951

#SPJ12

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lutik1710 [3]

<u>Answer:</u> The percentage by mass of NaCl in the mixture is 38.5 %

<u>Explanation:</u>

To calculate the mass percentage of element in compound, we use the equation:

\text{Mass percent of element}=\frac{\text{Mass of element}}{\text{Mass of compound}}\times 100      .......(1)

  • <u>For NaCl:</u>

Mass of sodium element = 23 g

Mass of NaCl = 58.5 g

Putting values in equation 1, we get:

\text{Mass percent of sodium element}=\frac{23g}{58.5g}\times 100=39.32\%

Mass fraction of sodium metal in NaCl = 0.3932

  • <u>For NaNO_3 :</u>

Mass of sodium element = 23 g

Mass of NaNO_3 = 85 g

Putting values in equation 1, we get:

\text{Mass percent of sodium element}=\frac{23g}{85g}\times 100=27.1\%

Mass fraction of sodium metal in sodium nitrate = 0.271

Let us assume the mass fraction of NaCl in the mixture is 'x'

So, the mass fraction of NaNO_3 in the mixture will be '(1-x)'

We are given:

Percent by mass of Na in the mixture = 31.8 %

Mass fraction of Na in the mixture = 0.318

Evaluating the mass fraction of NaCl in the mixture:

[(x\times 0.3932)+((1-x)\times 0.271)]=0.318

x = 0.385

Percent by mass of NaCl in the mixture will be = (0.385\times 100)=38.5\%

Hence, the percentage by mass of NaCl in the mixture is 38.5 %

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a bottle of acetone contains 55.0mL of acetone. If the acetone has a mass of 43.6 g. What is the density of acetone
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Answer:

792.72g/L

Explanation:

density formula

density = mass/volume in L

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Answer : The reaction 2 is spontaneous.

Explanation :

As we know that:

\Delta G= +ve, reaction is non spontaneous

\Delta G= -ve, reaction is spontaneous

\Delta G= 0, reaction is in equilibrium

For the reaction to be spontaneous, the Gibbs free energy of the reaction must come out to be negative.

Reaction 1:

Glucose + Pi \rightarrow glucose-6-phosphate + H₂O,   ΔG = +13.8 kJ/mol

Reaction 2:

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The answer to your question is A. Ionic

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b) Covalent bonds are bonds between two nonmetals. The elements share electrons so these bonds are not as stronger as Ionic bonds, the melting and boiling points are high.

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