A spring is pulled to 10cm and held in place with a force of 500N. What is the spring constant of the spring

In 1656, the Burgmeister (mayor) of the town of Magdeburg, Germany, Otto Von Guericke, carried out a dramatic demonstration of t

kakasveta [241]

The values of the required solutions are

F= 53731 N
N=37.05

<h3>What is the minimum number of horses required?</h3>

What is Force?

In the field of physics, an influence that can alter the motion of an object is referred to as a force. An object having mass can experience a change in its velocity, often known as an acceleration, when subjected to a force. Intuitively, force can also be conceptualized as either a push or a pull. Because it may be measured in both magnitude and direction, a force is considered a vector quantity.

What is atmospheric pressure?

The pressure that is exerted within the atmosphere of the Earth is referred to as barometric pressure as well as atmospheric pressure. As a unit of pressure, the standard atmosphere is defined as having a value of 101,325 Pa. This value is equivalent to 1013.25 millibars, 760 mm Hg, 29.9212 inches Hg, or 14.696 psi.

In most situations, the equation for force can be expressed numerically as

Force = pressure * A

Therefore

$F= (970 - 15 B)(\pi * (0.430 )^2)$

F= 53731 N

In conclusion, If each horse can pull with a force of 1450N

The number of horses required is

$N=\frac{60754 }{1450}$

N=37.05

Read more about Force

brainly.com/question/13191643

#SPJ1

7 0

2 years ago

You are trying to take an image of a particular star with apparent magnitude m=10, and need to figure out how long you will need

Natalka [10]

You haven't told us anything about the detectors being used. We don't know how the sensitivity of the detector is related to the total number of photons absorbed, and we don't even know whether you and your friend are both using the same type of detector.

All we can do, in desperation, is ASSUME that the minimum time required to just detect a star is inversely proportional to the total number of its photons that strike the detector. That is, assume . . .

(double the number of photons) ===> (detect the source in half the time) .

-- The intensity of light delivered to the prime focus of a telescope is directly proportional to the AREA of its objective lens or mirror, which in turn is proportional to the square of its radius or diameter.

So your telescope gathers (0.18/0.05)² = 12.96 times as much light as your friends telescope does.

-- So we'd expect your instrument to detect the same star in

(119.5 min) / (12.96) = <em>9.22 minutes .</em>

We're simply comparing the performance of two different telescopes as they observe the same object, so the star's magnitude doesn't matter.

3 0

4 years ago

Is the refraction different entering medium that has a higher index of refraction compared to entering amedium that has a lower

oee [108]

Answer:

Yes

Explanation:

The speed of light when it travels through glass, diamond, etc, the light travels at different speed from the speed of light. Speed of the light in material is related to the index of refraction.

The change in speed which occurs when the light passes from one medium to the another is responsible for bending of the light which is called as refraction.

<u>When the light goes into a medium with the higher index of the refraction, light bends towards normal. Conversely, if the light traveling goes from higher refractive index to lower refractive index, it will bend away from the normal. </u>

<u>Hence, the refraction is different in both the scenario.</u>

6 0

3 years ago

A recent study found that electrons that have energies between 3.45 eV and 19.9 eV can cause breaks in a DNA molecule even thoug

vlada-n [284]

Answer:

The Minimum wavelength is $\lambda_{min}= 382.2nm$

The Maximum wavelength is $\lambda_{max}= 624.2nm$

Explanation:

From the question we are told that

The energy range is $E_r = 3.25eV \ and \ 19.9eV$

Considering $E = 19.9eV$

When a single photon is transferred to to an electron the energy obtained can be calculated as follows

$E = 19.9eV = 19.9 *1.6 *10^{-19}J$

This energy is mathematically represented as

$E = \frac{hc}{\lambda_{max}}$

Here h is the Planck's constant with value of $h= 6.625*10^{-34}J\cdot s$

c is the speed of light with value of $c = 3*10^8 m/s$

Substituting values and making $\lambda$ the subject of the formula

$\lambda_{max} = \frac{hc}{E}$

$= \frac{6.625*10^{-34} * 3.0*10^{8}}{19.9*1.6*10^{-19}}$

$\lambda_{max}= 624.2nm$

Considering $E = 3.25eV$

When a single photon is transferred to to an electron the energy obtained can be calculated as follows

$E = 19.9eV = 3.25 *1.6 *10^{-19}J$

This energy is mathematically represented as

$E = \frac{hc}{\lambda_{min}}$

Substituting values and making $\lambda$ the subject of the formula

$\lambda_{min} = \frac{hc}{E}$

$= \frac{6.625*10^{-34} * 3.0*10^{8}}{3.25*1.6*10^{-19}}$

$\lambda_{min}= 382.2nm$

3 0

3 years ago

The initial concentration of acid ha in solution is 0.39 m. if the ph of the solution at equilibrium is 0.76, what is the percen

Alexus [3.1K]

The percent ionization of the acid is 44.56%

<h3>How can we calculate the percent ionization of the acid?</h3>

To calculate the percent ionization of the acid we are using the formula,

The H⁺ ion concentration [H⁺] = C x,

where, we are given,

C= concentration of the acid.

=0.39 M

x= degree of dissociation of the acid.

And one more thing we are given that, the pH of the acid=0.76.

So from the above statement we can say that,

pH = - log [H⁺]

Or,0.76 = -log [H⁺]

Or, log [H⁺] = -0.76

Or, [H⁺] = antilog -0.76

Or,[H⁺]= 10^-0.76

Or,[H⁺]=0.1738.

Now from the above calculation we know, the H⁺ ion concentration= 0.1738 M.

Now we put the known values in the above equation,

[H+]= Cx

Or,0.1739= 0.39 x

Or, x= 0.4459

From the above calculation we can conclude that the percent Ionization of the acid= 0.4459 X 100= 44.59%≈45%

Learn more about Ionization:

brainly.com/question/1445179

#SPJ4

4 0

1 year ago