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julsineya [31]
3 years ago
12

Draw the bridged bromonium ion that is formed as an intermediate during the bromination of this alkene. include hydrogen atoms,

nonbonding electrons, and formal charge(s) in your structure.

Chemistry
1 answer:
gogolik [260]3 years ago
6 0
<h2>Answer</h2>

Bromination:

Any reaction or process in which bromine (and no other elements) are introduced into a molecule.

Bromonium Ion:

The bromonium ion is formed when alkenes react with bromine. When the π cloud of the alkene (acting as a nucleophile) approaches the bromine molecule (acting as an electrophile), the σ-bond electrons of Br2 are pushed away, resulting in the departure of the bromide anion.(2)

Mechanism:

Step 1:

In the first step of the reaction, a bromine molecule approaches the electron-rich alkene carbon–carbon double bond. The bromine atom closer to the bond takes on a partial positive charge as its electrons are repelled by the electrons of the double bond. The atom is electrophilic at this time and is attacked by the pi electrons of the alkene [carbon–carbon double bond]. It forms for an instant a single sigma bond to both of the carbon atoms involved (2). The bonding of bromine is special in this intermediate, due to its relatively large size compared to carbon, the bromide ion is capable of interacting with both carbons which once shared the π-bond, making a three-membered ring. The bromide ion acquires a positive formal charge. At this moment the halogen ion is called a "bromonium ion".

Step 2:

When the first bromine atom attacks the carbon–carbon π-bond, it leaves behind one of its electrons with the other bromine that it was bonded to in Br2. That other atom is now a negative bromide anion and is attracted to the slight positive charge on the carbon atoms. It is blocked from nucleophilic attack on one side of the carbon chain by the first bromine atom and can only attack from the other side. As it attacks and forms a bond with one of the carbons, the bond between the first bromine atom and the other carbon atoms breaks, leaving each carbon atom with a halogen substituent.

In this way the two halogens add in an anti addition fashion, and when the alkene is part of a cycle the dibromide adopts the trans configuration.

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6 0
3 years ago
Automobile airbags contain solid sodium azide, nan3, that reacts to produce nitrogen gas when heated, thus inflating the bag.
forsale [732]

The values of work, w, for the system if 16.5 g NaN 3 reacts completely at 1.00 atm and 22 ∘ C. The work done is -919 J.

The equation of the reaction is;

2 NaN 3 ( s ) ⟶ 2 Na ( s ) + 3 N 2 ( g )

Number of moles of NaN3 = 16.5 g/65 g/mol = 0.25 moles

If 2 moles of NaNa3 yields 3 moles of N2

0.25 moles of NaN3 yields  0.25 moles × 3 moles/2 moles

= 0.375 moles of N2

We need to find the volume change using the;

PV = nRT

P = 1.00 atm

V =?

n =  0.375 moles of N2

R = 0.082 atmLK-1mol-1

T =  22 ∘ C + 273 = 295 K

V = nRT/P

V = 0.375 × 0.082  × 295/ 1.00

V = 9.07 L

Recall that during expansion the gas does work. Work done by the gas is;

W = -PΔV

W =-( 1 atm × 9.07 L)

W = -9 Atm

Again;

1 L atm = 101.325 J

So,

-9 atmL =  -9 atmL × 101.325 J/1 L atm

= -919 J

The work done is -919 J.

Learn more about work done here:-brainly.com/question/25573309

#SPJ4

<u>Disclaimer:- your question is incomplete, please see below for the complete question.</u>

Automobile airbags contain solid sodium azide, NaN 3, that reacts to produce nitrogen gas when heated, thus inflating the bag. 2 NaN 3 ( s ) ⟶ 2 Na ( s ) + 3 N 2 ( g ) Calculate the value of work, w, for the system if 16.5 g NaN 3 reacts completely at 1.00 atm and 22 ∘ C.

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