Given:

frequency, f = 60.0 Hz
frequency, f' = 45.0 Hz

Solution:
To calculate max current in inductor,
:
At f = 60.0 Hz


L = 0.1326 H
Now, reactance
at f' = 45.0 Hz:


Now,
is given by:
Therefore, max current in the inductor,
= 2.13 A
Answer:
a)σ₁ = 265.2 MPa
b)σ₂ = -172.8 MPa
c)
d)Range = 438 MPa
Explanation:
Given that
Mean stress ,σm= 46.2 MPa
Stress amplitude ,σa= 219 MPa
Lets take
Maximum stress level = σ₁
Minimum stress level =σ₂
The mean stress given as


2 x 46.2 = σ₁ + σ₂
σ₁ + σ₂ = 92.4 MPa --------1
The amplitude stress given as


2 x 219 = σ₁ - σ₂
σ₁ - σ₂ = 438 MPa --------2
By adding the above equation
2 σ₁ = 530.4
σ₁ = 265.2 MPa
-σ₂ = 438 -265.2 MPa
σ₂ = -172.8 MPa
Stress ratio



Range = 265.2 MPa - ( -172.8 MPa)
Range = 438 MPa
Answer:
I am not sure I am understanding plz more context
Explanation:
Answer:
a. 318.2k
b. 45.2kj
Explanation:
Heat transfer rate to an object is equal to the thermal conductivity of the material the object is made from, multiplied by the surface area in contact, multiplied by the difference in temperature between the two objects, divided by the thickness of the material.
See attachment for detailed analysis