Answer:
d= 4.079m ≈ 4.1m
Explanation:
calculate the shaft diameter from the torque, \frac{τ}{r} = \frac{T}{J} = \frac{C . ∅}{l}
Where, τ = Torsional stress induced at the outer surface of the shaft (Maximum Shear stress).
r = Radius of the shaft.
T = Twisting Moment or Torque.
J = Polar moment of inertia.
C = Modulus of rigidity for the shaft material.
l = Length of the shaft.
θ = Angle of twist in radians on a length.
Maximum Torque, ζ= τ × \frac{ π}{16} × d³
τ= 60 MPa
ζ= 800 N·m
800 = 60 × \frac{ π}{16} × d³
800= 11.78 × d³
d³= 800 ÷ 11.78
d³= 67.9
d= \sqrt[3]{} 67.9
d= 4.079m ≈ 4.1m
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Plan, design, and implement solar energy projects
Answer:
The diffusion coefficients for iron in nickel are given at two temperatures:
T (K) 1273 1473
D (
/s) 9.4 ×
2.4 × 
(a) Determine the values of Do and the activation energy Qd.
(b) What is the magnitude of D at 1100°C (1373 K)?
<em>A </em>
<em>The pre-exponential factor Do = 2.1 x </em>
<em></em>
<em>The activation energy Qd = 252,609 J/mol</em>
<em>B</em>
<em>The diffusion coefficient D= 5.14 x </em>
<em></em>
Explanation:
The full explanation is contained in the attached images;