The quantity of heat absorbed is 33.4 kJ.
Δ<em>H</em>_fus = 334 J·g⁻¹
<em>q = m</em>Δ<em>H</em>_fus = 100.0 g × 334 J·g⁻¹ = 3.34 × 10⁴ J = 33.4 kJ
Answer:
hco I believe
Explanation:
Pretty sure about this, when do you need to put it in?
what is that i connot understand your question
im sorry i connot answer your question
c. liquid and gas
its obvious, lol.
