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Nutka1998 [239]
3 years ago
11

Help!! I’ll give brainliest!! Which person will hear the highest pitch?

Physics
2 answers:
Ad libitum [116K]3 years ago
5 0
I believe person A will have the highest pitch
GarryVolchara [31]3 years ago
5 0
Person C will because the higher pitch is always moving towards the observer.
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When trying to simplify and find the equivalent resistance you should first simplify resistors in _ before simplifying those in
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Example problem circuit with a pair of parallel resitiors in series with another resistors. Figure 2 solution. We start by simplifying the parallel l...
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3 years ago
On what principle does a bottle opener work
Genrish500 [490]

Answer:

Bottle opener works on a fulcrum.

Explanation:

A bottle opener is a second-class lever because the pivot point is at one end of the opener and the load is in the middle.

4 0
3 years ago
A hydraulic car jack needs to be designed so it can lift a 2903.57 lb car assuming that a person can exert a force of 24.41 lbs.
marishachu [46]

Answer:

Diameter of the piston would be 0.71 m (71.1 cm)

Explanation:

From the principle of pressure;

\frac{F_{1} }{A_{1} } = \frac{F_{2} }{A_{2} }

Let F_{1} = 2903.57 lb, F_{2} = 24.41 lbs, r_{2} = 3.26 cm = 0.0326 m.

A_{2} = \pi r^{2}

    = \frac{22}{7} x (0.0326)^{2}

    = 0.00334 m^{2}

So that:

\frac{2903.57}{A_{1} } = \frac{24.41}{0.00334}

A_{1} = \frac{2903.57*0.00334}{24.41}

    = 0.3973

A_{1} = 0.4 m^{2}

The radius of the piston can be determined by:

A_{1} = \pi r^{2}

0.3973 = \frac{22}{7} x r^{2}

r^{2} = \frac{0.3973*7}{22}

   = 0.1264

r = \sqrt{0.1264}

 = 0.3555

r = 0.36 m

Diameter of the piston = 2 x r

                                     = 2 x 0.3555

                                     = 0.711

Diameter of the piston would be 0.71 m (71.1 cm).

4 0
3 years ago
The tenth pair of cranial nerves is the longest in the body and leaves by way of the jugular foramen. These nerves are called th
tekilochka [14]

Answer:

Vagus nerves

Explanation:

The vagus nerves are the tenth pair of cranial nerves

4 0
3 years ago
A 190 mH inductor is connected to an emf given by
Bas_tet [7]

(a) The reactance of the inductor is 25.46 ohms.

(b) The expression for the current through the inductor is I(t) = (6.32 A) sin(134t)

<h3>Ractance of the inductor</h3>

The reactance of the inductor is calculated as follows;

XL = ωL

where;

  • ω is angular frequency
  • L is 190 mH

v(t) = (161 V) sin(134t)

v(t) =  V sin(ωt)

The reactance of the inductor is calculated as follows;

XL = (134) x (190 x 10⁻³)

XL = 25.46 ohms

<h3>Peak current in the circuit</h3>

I₀ = V₀/XL

I₀ = (161) / (25.46)

I₀ = 6.32 A

<h3>Expression for the current through the inductor</h3>

I(t) = (6.32 A) sin(134t)

Learn more about inductance here: brainly.com/question/16765199

7 0
2 years ago
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