<span>When the electron in a hydrogen atom transitions from a high energy state to a lower energy state, the energy lost from the electron is used to produce a photon corresponding to the loss of energy. That photon will correspond to exactly 1 wavelength. And since a hydrogen atom has only 1 electron, at any given moment, it can only produce 1 photon. And in order to simultaneously produce 4 photons for 4 spectral lines, that would require a simultaneous transition of 4 electrons which is 3 too many for a hydrogen atom.</span>
Answer:
Yes they do,
Explanation:
The spitting is called dissociation
Explanation:
question 44
the number 35 of bromine represents the atomic number
question 45
29 protons,
27 electrons
29-27 = +2
the charge on the following particle is
+2
Answer:
How many 250 mg tablets of metronidazole are needed to make 150 mL of suspension containing
100 mg/mL?
a. 25
b. 30
c.50
d. 60
Explanation:
<em>if </em><em> </em><em>mali </em><em>po </em><em>I'm</em><em> </em><em>so </em><em>sorry</em>
Answer: Option (d) is the correct answer.
Explanation:
It is given that molecular formula is
. Now, we will calculate the degree of unsaturation as follows.
Degree of unsaturation = 
= 
= 9 - 8 + 1
= 2
As the degree of unsaturation comes out to be 2. It means that this compound will contain one ring and one double bond.
Yes, this compound could be an alkyne as for alkyne D.B.E = 2.
But this compound cannot be a cycloalkane because for a cycloalkane D.B.E = 1 which is due to the ring only.
Thus, we can conclude that it is a cycloalkane is not a structural possibility for this hydrocarbon.