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larisa [96]
3 years ago
9

What does the energy of an electromagnetic wave depend on?

Physics
1 answer:
Mrrafil [7]3 years ago
6 0
It depends on frequency
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A SDOF undamped system is set into free vibration with an initial displacement and an initial velocity. The mass of the system i
loris [4]

Answer:

Explanation:

stiffness k = 160

m = 10

angular frequency ω = \sqrt{\frac{k}{m} }

= \sqrt{\frac{160}{10} }

= 4

ω  = 4

Let x = 4 - A sinωt

when t = 0

x = 4 in

when t = 2 s , x = - 4

- 4 = 4 - A sinωt

8  = A sin 4 x 2

8 = A sin8

A = 8 / sin 8

= 8 / .989

= 8.09 in .

x = 4 - A sinωt

dx / dt = - Aω cosωt

v =  - Aω cosωt

for t = 0

v = - Aω

= - 8.09 x 4

= - 32.36 in / s

initial velocity v = - 32.36 in /s

displacement x for t = 4s

x = 4 - 8.09 sin 4 x 4

= 4 - 8.09 sin 16

= 4 - 8.09 x - .2879

= 4 + 2.33

= 6.33  in.

c ) Amplitude of vibration A = 8.09 in .as calculated above .

4 0
3 years ago
A man weighing 680N and a woman weighing 500N have the same momentum. What is the ratio of the man's kinetic energy Km to that o
svet-max [94.6K]

Answer:

\dfrac{K_m}{K_w}=0.734

Explanation:

given,

weight of the man = 680 N

weight of the woman = 500 N

mass of man = \dfrac{680}{9.8}

  M_m = 69.4 Kg

mass of woman

= \dfrac{500}{9.8}

M_w = 51 Kg

ratio of man's kinetic energy Km to that of the woman Kw

\dfrac{K_m}{K_w}=\dfrac{\dfrac{P_m^2}{2M_m}}{\dfrac{P_w^2}{2M_w}}

momentum is same

\dfrac{K_m}{K_w}=\dfrac{2M_w}{2M_m}

\dfrac{K_m}{K_w}=\dfrac{M_w}{M_m}

\dfrac{K_m}{K_w}=\dfrac{51}{69.4}

\dfrac{K_m}{K_w}=0.734

3 0
4 years ago
Suppose that a car starts from rest at t = 0. The car moves with an acceleration of 1.5 m/s2. How far will the car travel in 3.0
rodikova [14]

Answer:

6.75m

Explanation:

To calculate the distance in this question, we can use the formula:

S = ut + 1/2at^2

Where; S = distance

u = initial velocity = 0m/s

t = 3s

a = 1.5m/s^2

Hence:

S = (0 × 3) + 1/2 (1.5 × 3 × 3)

S = 0 + 1/2 (13.5)

S = 13.5/2

S = 6.75

Therefore, the car will travel 6.75m in 3seconds.

3 0
4 years ago
Calculate the potential at the center of curvature of the arc if the potential is assumed to be zero at infinity.
yan [13]

the potential at the center of curvature of the arc = v = Q ∕ (4πε∘a) or \frac{kQ}{a}

ATQ,

We have density of charge,

λ = \frac{Q}{L}

Where L is the rod's length, in this case the semicircle's length L = πr

Q is the charge on the rod

The potential created at the center by an differential element of charge is:

k = \frac{dQ}{r}

where k is the coulomb's constant

r is the distance from dQ to center of the circle

v = ∫ \frac{K dQ}{a} , Where a = radius, k = 1 / 4πε∘

v =\frac{kQ}{a} or Q ∕ (4πε∘a)

To learn more about potential from the given link

brainly.com/question/25923373

#SPJ4

6 0
2 years ago
A kilogram is a unit of mass and when multiplied by meters per second
amm1812

Answer:

it yields a derived unit known as Newton, which is the unit of Force.

Explanation:

The formula for force is given by Newton's Second Law, which states that whenever an unbalanced force is applied to a body, it produces an acceleration in the body in the direction of force.

F = ma\\

where, F = Force

m = mass

a = acceleration

Now, we substitute the respective S.I units of each quantity in equation:

F = Newton (N)

m = kilogram (kg)

a = acceleration = m/s²

Therefore,

N = (kg)(m/s^2)

So, it is clear from above expression that:

<u>When kilogram is multiplied by meter per second squared, it yields a derived unit known as Newton, which is the unit of Force.</u>

5 0
3 years ago
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