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pashok25 [27]
3 years ago
12

Mrs. Smith is demonstrating a chemical change for her class. She places 15 grams of baking soda into a beaker. Next she adds 15

grams of vinegar to the same beaker. When the two compounds make contact, they bubble and fizz a great deal. She places the beaker on the balance and notes that the mass of the solution in the beaker is less than the expected 30 grams. Why is the mass of the solution in the beaker less than 30 grams? A) The balance was not working correctly. B) The gas that was released changed the mass. C) Mass is always lost in a chemical reaction. D) The new products have less mass than the original reactants.
Chemistry
2 answers:
crimeas [40]3 years ago
6 0

Answer:

B) The gas that was released changed the mass.

Explanation:

In the acid base reaction of vinegar and sodium bicarbonate, sodium acetate, water and carbon dioxide are formed.

C_{2}H_{4} O_{2}+NaHCO_{3}  → NaC_{2} H_{3}O_{2} +H_{2} O+CO_{2}↑

Carbon dioxide is released from the beaker in the form of gas (as can be seen in the previous reaction), which is due to the loss of mass observed. This compound is responsible for the formation of bubbles in the reaction.

vichka [17]3 years ago
4 0

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

∴ B is the Answer

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3 years ago
Atmospheric chemistry involves highly reactive, odd-electron molecules such as the hydroperoxyl radical HO2, which decomposes in
dem82 [27]

Answer:

Rate = k [HO2]

Rate constant = 0.8456us-1

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Time(us) 0 0.6 1.0 1.4 1.8 2.4

[HO2](uM) 8.5 5.1 3.6 2.6 1.1 1.1

The rate law is given as;

Rate = k [HO2]^x

Where x signify the order of reaction.

For an order of reaction, the rate constant is constant for all concentrations. We are going to use this to obtain the order of reaction.

Zero Order:

[A] = [A]o -kt

5.1 = 8.5 - k(0.6)

-k (0.6) = 5.1 - 8.5

k = 5.67

3.6 = 5.1 - k(0.4)

-k (0.4) = 3.6 - 5.1

k = 3.75

The fact that the rate constant was not constant means the reaction is not a zero order reaction.

First Order:

ln[A] = ln[A]o -kt

(5.1) = ln(8.5) - k(0.6)

-k (0.6) = ln(5.1) - ln(8.5)

k = 0.8524

ln(3.6) = ln(5.1) - k(0.4)

-k (0.4) = ln(3.6) - ln(5.1)

k = 0.8708

ln(2.6) = ln(3.6) - k (0.4)

-k (0.4) = ln(2.6) - ln(3.6)

k = 0.8136

From the three calculations we see that the value of the rate constant is fairly constant in the range of 0.8 This means our reaction is a first order reaction.

The rate law is given as;

Rate = k [HO2]

We can represent the rate constant as the average of the three rate constants calculated above;

Rate constant = (0.8136 + 0.8708 + 0.8524 / 3)

Rate constant = 0.8456us-1

6 0
3 years ago
If total pressure of multiple gases is 512 mmHg, and the pressure of oxygen gas is 332 mmHg and the pressure of carbon monoxide
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Answer: 67 mmHg

Explanation:

According to Dalton's Gas Law, the total pressure of a mixture of gases is the sum of the pressure of each individual gas.

i.e Ptotal = P1 + P2 + P3 + .......

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P(carbon mono-oxide) = 113 mmHg

Remaining pressure (P3) = ?

To get P3, apply Dalton's Gas Law formula

Ptotal = P(oxygen) + P(carbon mono-oxide) + P3

512 mmHg = 332 mmHg + 113 mmHg + P3

512 mmHg = 445 mmHg + P3

P3 = 512 mmHg - 445 mmHg

P3 = 67 mmHg

Thus, the remaining pressure is 67 mmHg

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3 years ago
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