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LenKa [72]
3 years ago
14

A tank containing oxygen, carbon dioxide, and nitrogen gases has a total pressure of 6.7

Chemistry
1 answer:
ollegr [7]3 years ago
7 0

Answer:

P(N₂) = 2.5 atm

Explanation:

Given data:

Total pressure of gasses = 6.7 atm

Partial pressure of O₂ = 3.0 atm

Partial pressure of CO₂ = 1.2 atm

Partial pressure of N₂ = ?

Solution;

According to Dalton law of partial pressure,

The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.

Mathematical expression:

P(total) = P₁ + P₂ + P₃+ ............+Pₙ

Now we will solve this  problem by using this law.

P(total) = P(O₂)  + P(CO₂) + P(N₂)

6.7 atm = 3.0 atm + 1.2 atm + P(N₂)

6.7 atm = 4.2 atm + P(N₂)

P(N₂) = 6.7 atm - 4.2 atm

P(N₂) = 2.5 atm

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Hope this helps!
8 0
3 years ago
Consider this initial-rate data at a certain temperature for the reaction described by N2O3(
Yuliya22 [10]

<span><span>N2</span><span>O3</span><span>(g)</span>→NO<span>(g)</span>+<span>NO2</span><span>(g)</span></span>

<span><span>[<span>N2</span><span>O3</span>]</span> Initial Rate</span>
<span>0.1 M     r<span>(t)</span>=0.66</span> M/s
<span>0.2 M     r<span>(t)</span>=1.32</span> M/s
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We can have the relationship:

<span>(<span><span>[<span>N2</span><span>O3</span>]/</span><span><span>[<span>N2</span><span>O3</span>]</span>0</span></span>)^m</span>=<span><span>r<span>(t)/</span></span><span><span>r0</span><span>(t)
However,
</span></span></span>([N2O3]/[N2O3]0) = 2

Also, we assume m=1 which is the order of the reaction.

Thus, the relationship is simplified to,

r(t)/r0(t) = 2

r<span>(t)</span>=k<span>[<span>N2</span><span>O3</span>]</span>

0.66 <span>M/s=k×0.1 M</span>

<span>k=6.6</span> <span>s<span>−<span>1</span></span></span>

6 0
3 years ago
Read 2 more answers
What should the positive charge be on the<br> Fe ion to balance out the -3 charge from<br> the CI?
Dmitry [639]
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3 0
3 years ago
Two substances A and B, initially at different temperatures, are thermally isolated from their surroundings and allowed to come
Elden [556K]

Answer:

B

Explanation:

For solving this we need a heat balance

Q_{a} = Q_{b}\\m_{a}*C_{a}*\Delta T_{a} = m_{b}*C_{b}*\Delta T_{b}

By changing the corresponding relations, we have

m_{a}*C_{a}*\Delta T_{a} = \frac{1}{2}m_{a}*4C_{a}*\Delta T_{b} \\\\\\

By cancelling similar factor, we obtain

\Delta T_{a} = 2 \Delta T_{b}\\\frac{\Delta T_{a}}{\Delta T_{b}} = 2\\

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3 0
3 years ago
Is Orange Juice with Pulp is Heterogeneous<br> or Homogeneous Mixture?
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Answer:

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8 0
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