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Law Incorporation [45]
4 years ago
15

The speedometer of a car moving to the east reads 55 mph. It passes another car that moves to the west at 55 mph. The cars have

the same ____.
A. velocity
B. speed
C. same speed and velocity
D. neither the same speed nor the same velocity
Physics
2 answers:
olya-2409 [2.1K]4 years ago
8 0

The answer is B.

This is because both cars are moving at the same speed, but have different velocities due to the different directions they are moving in.

BlackZzzverrR [31]4 years ago
7 0

Answer: The correct answer is B.

Explanation:

Speed is the scalar quantity. It has magnitude only. For example, the car is moving with the speed of 60 km per hour.

The velocity is the vector quantity. It has magnitude as well as direction.

For example, the car is moving with the velocity of 60 km per hour in the north direction.

In the given problem, the speedometer of a car moving to the east reads 55 mph. It passes another car that moves to the west at 55 mph.

In this case, the speed is same which is equal to 55 mph but the velocities are different as the directions of the cars are different. The velocities of the cars are 55 mph to the east direction and 55 mph to the west direction.

Therefore, the cars have the same speed.

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Which SI unit is the correctly abbreviated for describing the mass on an object.
djverab [1.8K]
S.I. Unit of mass is Kilogram which is denoted by Kg

In short, Your Answer would be Option C

Hope this helps!
4 0
3 years ago
If you double the pressure on the surface of a can of water, the buoyant force on a stone placed in that water will
Bingel [31]
The buoyant force won't change.
4 0
3 years ago
Do the math: How many seconds would it take an echo sounder’s ping to make the trip from a ship to the Challenger Deep (10,994 m
Lera25 [3.4K]

Answer:

<h2>14.66secs</h2>

Explanation:

Given the formula for calculating the depth in metres expressed as

depth in meters = ½ (1500 m/sec × Echo travel time in seconds)

Given depth of the challenger = 10, 994 meters, we will substitute this given value into the formula given to calculate the time take for the echo to travel.

10, 994 = depth in meters = ½ * 1500 m/sec × Echo travel time in seconds

10,994 = 750 * Echo travel time in seconds

Dividing both sides by 750;

Echo travel time in seconds = 10,994 /750

Echo travel time in seconds ≈ 14.66secs (to two decimal places)

Therefore, it would take an echo sounder’s ping 14.66secs to make the trip from a ship to the Challenger Deep and back

6 0
3 years ago
What are the dimensions of potential energy?​
Pachacha [2.7K]

Potential Energy (P.E) = Mass x

Acceleration due to Gravity x Altitude. Putting this value in the above equation we get, Dimensional Formula of

Potential energy= M1L2T-2.

5 0
3 years ago
Why won’t anyone help me please anybody help me I really need help .
irga5000 [103]

Answer:

1➡️ this is the method of decomposition

2➡️ H2 and O2

3➡️ b

sorry if I am wrong

8 0
3 years ago
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