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olga nikolaevna [1]
3 years ago
5

The boiling point of an aqueous solution is 102.08 °C. What is the freezing point? Constants can be found here.

Chemistry
1 answer:
enyata [817]3 years ago
7 0

Colligative properties calculations are used for this type of problem. Calculations are as follows:<span>


ΔT(freezing point)  = (Kf)(molality)
ΔT(freezing point)  = 1.86 °C kg / mol (molality)
 </span>Tf - 102.08 = 1.86m

Tf = 1.86m + 102.08

The concetration of the solution is needed in order to obtain a specific value.

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