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Len [333]
3 years ago
9

What is the best coefficient of performance for a refrigerator that cools an environment at -26.0°C and has heat transfer to ano

ther environment at 50.0°C?
Physics
1 answer:
azamat3 years ago
6 0

Answer:

COP = 4.25

Explanation:

It is given that,

Cooling temperature, T_c=-26^{\circ}C=273-26=247\ K

Heating temperature, T_h=50^{\circ}C=323\ K

We need to find the coefficient of performance. It is given by :

COP=\dfrac{T_h}{T_h-T_c}

COP=\dfrac{323}{323-247}

COP = 4.25

So, the best coefficient of performance of a refrigerator is 4.45 Hence, this is the required solution.

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Explanation:

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A particular inductor is connected to a circuit where it experiences a change in current of 0.8 amps every 0.10 sec. If the indu
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Answer:

0.4

Explanation:

Given that a particular inductor is connected to a circuit where it experiences a change in current of 0.8 amps every 0.10 sec. If the inductor has a self-inductance of 2.0 V, what is the inductance

Using the power formula

P = IV

Substitute all the parameters

P = 0.8 × 2

P = 1.6 W

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Inductance = reciprocal of resistance

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3 years ago
a car with a mass of 2000 kilograms is moving around a circular curve at a uniform velocity of 25 meters per second. The curve h
melisa1 [442]
In the given problem, we say various information's that are going to help us reach the ultimate answer to the question. Let us first write the information's that have been presented in front of us.
Mass of the car = 2000 kg
Velocity of the car = 25 m/s^2
Radius of the circle = 80 m
Now we already know the equation for calculating the centripetal force and that is
Centripetal Force = [mass * (velocity)^2]/Radius
                            = [2000 * (25)^2]/80
                            = (2000 * 625)/80
                            = 1250000/80
                            = 15625
So the centripetal force on the car is 15625 Newtons
  
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Please find attached photograph for your answer. Hope it helps. Please do comment

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