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pshichka [43]
4 years ago
8

3) What is the weight of the ethyl alcohol that exactly fills a

Chemistry
1 answer:
Leto [7]4 years ago
3 0

Answer:

158g

Explanation:

To calculate the "weight" (mass) of ethyl alcohol, we have to use this formula:

- Density will have units of gmL when dealing with a liquid or units of gcm3 when dealing with a solid.

The mass has units of grams, g.

The volume will have units of mL or cm3

We are given the density and volume, both of which have good units so all we have to do is rearrange the equation to solve for the mass:

density×volume=massvolume×volume

Density×Volume = Mass

0.789gmL×200.0mL

Thus, ethyl alcohol weighs 158g.

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How many moles of nacl are required to make 250 ml of a 3.00 m solution?
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A sample of Xe gas is observed to effuse through a pourous barrier in 4.83 minutes. Under the same conditions, the same number o
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28.93 g/mol

Explanation:

This is an extension of Graham's Law of Effusion where \frac{R1}{R2} = \sqrt{\frac{M2}{M1} } = \frac{t2}{t1}

We're only talking about molar mass and time (t) here so we'll just concentrate on \sqrt{\frac{M2}{M1} } = \frac{t2}{t1}. Notice how the molar mass and time are on the same position, recall effusion is when gas escapes from a container through a small hole. The time it takes it to leave depends on the molar mass. If the gas is heavy, like Xe, it would take a longer time (4.83 minutes). If it was light it would leave in less time, that gives us somewhat an idea what our element could be, we know that it's atleast an element before Xenon.

Let's plug everything in and solve for M2. I chose M2 to be the unknown here because it's easier to have it basically as a whole number already.

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The square root is easier to deal with if you take it out in the first step, so let's remove it by squaring each side by 2, the opposite of square root essentially.

(\sqrt{\frac{M2}{131} } )^2= (\frac{2.29}{4.83})^2

{\frac{M2}{131} } = (0.47)^2

{\frac{M2}{131} } = 0.22

M2= 0.22 x 131

M2= 28.93 g/mol

8 0
3 years ago
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