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3 years ago

3) What is the weight of the ethyl alcohol that exactly fills a

Chemistry

1 answer:

Leto [7]3 years ago

3 0

Answer:

158g

Explanation:

To calculate the "weight" (mass) of ethyl alcohol, we have to use this formula:

- Density will have units of gmL when dealing with a liquid or units of gcm3 when dealing with a solid.

The mass has units of grams, g.

The volume will have units of mL or cm3

We are given the density and volume, both of which have good units so all we have to do is rearrange the equation to solve for the mass:

density×volume=massvolume×volume

Density×Volume = Mass

0.789gmL×200.0mL

Thus, ethyl alcohol weighs 158g.

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Note that hydrogen gas and oxygen gas are both biatomic molecules.

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Moles of potassium permanganate = 0.0008

<h3>Further explanation </h3>

Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution). Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range

Reaction

5Na2C2O4(aq) + 2KMnO4(aq) + 8H2SO4(aq) ---> 2MnSO4(aq) + K2SO4(aq) + 5Na2SO4(aq) + 10CO2(g) + 8H2O(1)

The end point ⇒titrant and analyte moles equal

titrant : potassium permanganate-KMnO4

analyte : sodium oxalate - Na2C2O4

so moles of KMnO4 = moles of Na2C2O4

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$\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{0.264}{134 g/mol}\\\\mol=0.002$

From equation, mol ratio Na2C2O4 : KMnO4 = 5 : 2, so mol KMnO4 :

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