Answer:
See explanation and image attached
Explanation:
The addition of hypohalous acids to alkenes follows the Markovnikov rule. This rule states that the negative part of the addendum is joined to the carbon atom with the least number of hydrogen atoms (more substituted carbon atom).
In the addition of hypohalous acids, the halogen is the positive end of the addendum and the OH^- is the negative end of the addendum. This explains the product shown in the image attached.
The equation in this problem is: 2Pb(NO3)2(s) --> 2PbO(s)
+ 4NO2(g) + O2(g)
And the question is what the pressure in the cylinder is
after decomposition and cooling to a temperature of 300 K.
Solution:
Moles of Pb (NO3)2 = 3.31/331 = 0.0100
2 moles of Pb (NO3)2 will decay to mold 4 moles of NO2 and 1 mole of O2. So
0.0100 moles of Pb (NO3)2 will form 0.02 moles of NO2 and 0.00500 moles of
O2
Then use the formula: PV = nRT.
P = (0.02 + 0.005) * 0.082 * 300 / 1.62
= 0.380 atm
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Because if you have a liquid then you need a glass to keep it together and when it is a solid it is already together so you don't need to do anything
<h3>Answer:</h3>
18.75 grams
<h3>Explanation:</h3>
- Half-life refers to the time taken by a radioactive material to decay by half of the original mass.
- In this case, the half-life of element X is 10 years, which means it takes 10 years for a given mass of the element to decay by half of its original mass.
- To calculate the amount that remained after decay we use;
Remaining mass = Original mass × (1/2)^n, where n is the number of half-lives
Number of half-lives = Time for the decay ÷ Half-life
= 40 years ÷ 10 years
= 4
Therefore;
Remaining mass = 300 g × (1/2)⁴
= 300 g × 1/16
= 18.75 g
Hence, a mass of 300 g of an element X decays to 18.75 g after 40 years.
