1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tamiku [17]
3 years ago
5

EMERGENCY OR I WILL FAIL PLS HELP I WILL MARK BRAINLIEST!!!!

Chemistry
1 answer:
Stella [2.4K]3 years ago
7 0

Answer:

1. sublimation

2.melting

3.melting  

4.sublimation

Explanation:

melting is a process when solid changes to liquid

Sublimation is the transition of a substance directly from the solid to the gas state, without passing through the liquid state.

You might be interested in
How many gallons in 2 L bottle
zepelin [54]
0.528 us liquid gallon
4 0
3 years ago
What is the MOLAR heat of combustion of methane(CH₄) if 64.00g of methane are burned to heat 75.0 ml of water from 25.00°C to 95
melamori03 [73]

Answer:

-5.51 kJ/mol

Explanation:

Step 1: Calculate the heat required to heat the water.

We use the following expression.

Q = c \times m \times \Delta T

where,

  • c: specific heat capacity
  • m: mass
  • ΔT: change in the temperature

The average density of water is 1 g/mL, so 75.0 mL ≅ 75.0 g.

Q = 4.184J/g.\°C \times 75.0g \times (95.00\°C - 25.00\°C) = 2.20 \times 10^{3} J = 2.20 kJ

Step 2: Calculate the heat released by the methane

According to the law of conservation of energy, the sum of the heat released by the combustion of methane (Qc) and the heat absorbed by the water (Qw) is zero

Qc + Qw = 0

Qc = -Qw = -22.0 kJ

Step 3: Calculate the molar heat of combustion of methane.

The molar mass of methane is 16.04 g/mol. We use this data to find the molar heat of combustion of methane, considering that 22.0 kJ are released by the combustion of 64.00 g of methane.

\frac{-22.0kJ}{64.00g} \times \frac{16.04g}{mol} = -5.51 kJ/mol

8 0
3 years ago
Who likes pomegranates
Sergio [31]

Answer:

I LIKE POMEGRANATES

Explanation

A LOT

8 0
3 years ago
Which of the following indicates the cathode rays has a large charge to mass ratio?
Anna007 [38]

Answer:

Gggg

Explanation:

8 0
3 years ago
A sample of benzene was vaporized at 25◦C. When 37.5 kJ of heat was supplied, 95.0 g of the liquid benzene vaporized. What is th
grandymaker [24]

Answer:

Enthalpy of vaporization = 30.8 kj/mol

Explanation:

Given data:

Mass of benzene = 95.0 g

Heat evolved = 37.5 KJ

Enthalpy of vaporization = ?

Solution:

Molar mass of benzene = 78 g/mol

Number of moles = mass/ molar mass

Number of moles = 95 g/ 78 g/mol

Number of moles = 1.218 mol

Enthalpy of vaporization =  37.5 KJ/1.218 mol

Enthalpy of vaporization = 30.8 kj/mol

8 0
3 years ago
Other questions:
  • Why does your finger seem to move? How is this related to the parallax of stars?
    10·1 answer
  • Hi All,
    14·1 answer
  • What is the organelle that packages and releases materials other parts of the cell?
    9·1 answer
  • A sample of 0.900 mol N2O is placed in a sealed
    12·1 answer
  • What mass of copper is equivalent to 0.7moles?​
    10·1 answer
  • How does Controlled fires help prevent real forest fires?
    15·1 answer
  • How many moles would there be in 500,000,000,000 atoms of silver? Show your calculation
    6·1 answer
  • Complete these chemical reactions.
    12·1 answer
  • Which substance freezes at the lowest temperature?<br> a Neon<br> b Argon<br> С Oxygen<br> d Water
    14·1 answer
  • Oxidation state of Nitrogen in N2O5​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!