Answer:
a. If the reaction mixture initially contains only OF2(g), then at equilibrium, the reaction mixture will consist of essentially only O2(g) and F2(g).
Explanation:
The answer is a) because the value for Kp is really close to zero (having x10⁻¹⁵), this means that at equilibrium O₂ and F₂ will be significantly more present than OF₂.
Sodium ions and sulfate ions shall be present in the solution.
Answer:
[See Below]
Explanation:
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→ <u>Conversion</u>:
→ <u>Write out an equation</u>:
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→ <u>So your answer would be</u>:
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D or A copy of the papers in my
Answer:
0.00375 moles OF KHP
Explanation:
Equation of reaction of NaOH and KHP :
KHC₈H₄ O₄(aq) + NaOH(aq) → NaKC₈H₄O₄(aq) + H₂O(l)
the reaction required 25ml
Molarity = no of mole / volume in liters
no of moles = Molarity × volume in liters
no of moles of NaOH = 0.150 × (25/1000) = 0.00375 moles
using the balanced equation above
1 mole of NaOH requires 1 mole of KHP
therefore
0.00375 mole of NaOH will require 0.00375 mole KHP.
