The atomic mass of K is 39
from Avogadro's law
39g of K contains 6.02x10^23 atoms
therefore if
39=6.02x19^23
X=5.11×10^22
making X the subject of the formula
X= (5.11×10^22×39)÷6.02×10^23
X= 33g
Helium has the smallest atomic radius® Α⇒Ω
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hope this helps!
Answer: -
A) 3.59
Explanation: -
The number of significant figures in 2.06 = 3
The number of significant figures in 1.743 = 4
The number of significant figures in 1.00 = 3
During multiplication of significant figures, the number of significant figures in the answer would be the smallest value that is 3 in this case.
2.06 x 1.743 x 1.00 = 3.5908.
The answer to 3 significant figures is
2.06 x 1.743 x 1.00 = 3.59
Thus, Andi when performs the calculation that is shown below.
(2.06)(1.743)(1.00)
the answer be reported using the correct number of significant figures as A) 3.59
