Answer:
it would cause global warming
Explanation: hope this helps
Answer:
63.01284 g/mol
Explanation:
This compound is also known as Nitric Acid.
Convert grams HNO3 to moles or moles HNO3 to grams
Molecular weight calculation:
1.00794 + 14.0067 + 15.9994*3
Percent composition by element
Element Symbol Atomic Mass # of Atoms Mass Percent
Hydrogen H 1.00794 1 1.600%
Nitrogen N 14.0067 1 22.228%
Oxygen O 15.9994 3 76.172%
Answer:
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Answer:
c) two different elements
Explanation:
A periodic table can be defined as the standard arrangement of chemical elements by atomic number, electronic configuration and chemical properties in a tabular form.
Generally, a proper representation of the mass number and atomic number of chemical elements is key and very important in chemistry.
Furthermore, as a rule, it should be noted that the mass number (nucleon number) is always larger than the atomic number(number of proton).
In the periodic table, all chemical elements are identified based on number of protons because it represents the atomic number.
This ultimately implies that, numbers of protons (atomic numbers) is used to differentiate an atom of one chemical element from the atom of another chemical element.
Hence, two atoms with different numbers of protons are two different elements.
For example, Hydrogen has one proton while Oxygen has 8 protons.
Answer:
23 L
Explanation:
We'll begin by converting celsius temperature to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 100 °C
Initial temperature (T₁) = 100 °C + 273
Initial temperature (T₁) = 373 K
Final temperature (T₂) = 50.5 °C
Final temperature (T₂) = 50.5 °C + 273
Final temperature (T₂) = 323.5 K
Finally, we shall determine the initial volume of gas. This can be obtained as follow:
Initial temperature (T₁) = 373 K
Final temperature (T₂) = 323.5 K
Final volume (V₂) = 20 L
Initial volume (V₁) =?
V₁/T₁ = V₂/T₂
V₁ / 373 = 20 / 323.5
Cross multiply
V₁ × 323.5 = 373 × 20
V₁ × 323.5 = 7460
Divide both side by 323.5
V₁ = 7460 / 323.5
V₁ = 23 L
Thus, the original volume of the gas is 23 L
