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anastassius [24]
3 years ago
8

In a chemical formula such as C6H12O6 and H2O, what do you call the little numbers below the normal line of text.

Chemistry
2 answers:
Morgarella [4.7K]3 years ago
3 0

These are called subscript number.

That is the number below the normal line of test are called subscript number.

This number indicate the indicate the number of atoms of the element present in the chemical formula.

In both of these C₆H₁₂O₆ and H₂O, the number written below the line of the text are called subscript numbers.

Firdavs [7]3 years ago
3 0

Answer:

subscript number

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it would cause global warming

Explanation: hope this helps

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What is the percent of hydrogen by mass in HNO3? (Molar<br> mass of HNO3 = 630 g/mol)
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63.01284 g/mol

Explanation:

This compound is also known as Nitric Acid.

Convert grams HNO3 to moles or moles HNO3 to grams

Molecular weight calculation:

1.00794 + 14.0067 + 15.9994*3

Percent composition by element

Element Symbol Atomic Mass # of Atoms Mass Percent

Hydrogen H 1.00794 1 1.600%

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Two atoms with different numbers of protons are what?
Gnom [1K]

Answer:

c) two different elements

Explanation:

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Generally, a proper representation of the mass number and atomic number of chemical elements is key and very important in chemistry.

Furthermore, as a rule, it should be noted that the mass number (nucleon number) is always larger than the atomic number(number of proton).

In the periodic table, all chemical elements are identified based on number of protons because it represents the atomic number.

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6 0
3 years ago
Please help no links
jarptica [38.1K]

Answer:

23 L

Explanation:

We'll begin by converting celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 100 °C

Initial temperature (T₁) = 100 °C + 273

Initial temperature (T₁) = 373 K

Final temperature (T₂) = 50.5 °C

Final temperature (T₂) = 50.5 °C + 273

Final temperature (T₂) = 323.5 K

Finally, we shall determine the initial volume of gas. This can be obtained as follow:

Initial temperature (T₁) = 373 K

Final temperature (T₂) = 323.5 K

Final volume (V₂) = 20 L

Initial volume (V₁) =?

V₁/T₁ = V₂/T₂

V₁ / 373 = 20 / 323.5

Cross multiply

V₁ × 323.5 = 373 × 20

V₁ × 323.5 = 7460

Divide both side by 323.5

V₁ = 7460 / 323.5

V₁ = 23 L

Thus, the original volume of the gas is 23 L

7 0
3 years ago
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