Answer: a) 112.88 * 10^3 N/C; b) The electric field point outward from the center of the sphere.
Explanation: In order to solve this problem we have to use the gaussian law so we use a gaussian surface at r=0.965 m and the electric flux is equal to Q inside/εo
E* 4*π*r^2= Q inside/εo
E= k*Q inside/r^2= 9*10^9*(6.53+5.15)μC/(0.965)^2=122.88 * 10 ^3 N/C
Answer:
work done = force x distance
Explanation:
F = 23 N
D = 2m
W = 23 * 2 = 46 J
Answer:
98.33 %
Explanation:
On an elliptical orbit, angular momentum will be conserved .
Angular momentum = I ω = mvR
So mv₁R₁ = mv₂R₂
= v₁R₁ = v₂R₂
where v₁ is velocity and R₁ radius in low orbit (perigee)and v₂ and R₂ is velocity and radius in high orbit ( apogee ).
Here R₁ = Radius of the earth , R₂ is distance between moon and earth.
R₁ / R₂ = 1/60
v₁ /v₂ = R₂ / R₁ = 60
v₂ / v₁ = 1 / 60
1 - (v₂ / v₁ ) = 1 -( 1 / 60)
(v₁ -v₂)/v₁ = ( 60-1 )/60
(v₁ -v₂)/v₁ x 100 = 5900/60 = 98.33 %