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kompoz [17]
3 years ago
12

calculate the average acceleration of a car with a starting velocity of 0 m/s that accelerates to 9 m/ s in 3 second

Physics
1 answer:
ladessa [460]3 years ago
6 0

Answer:

a = 3 m/s²

Explanation:

a = Δv/t

a = (vf - vi)/t

a = (9 - 0)/3

a = 3m/s²

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State one advantage and disadvantage of friction
yuradex [85]

Answer:

  1. Advantage: Helps us to walk without slipping.
  2. Helps machines work

Disadvantage:

  1. We slip on a wet floor.
  2. Causes the smoothness of tires and smoothness of shoes soul.

5 0
2 years ago
__________ research is designed to measure the association between variables that are not manipulated by the researcher.
Sliva [168]

Answer:

Option c. Correlational

Explanation:

Correlational research is basically a method of carrying out a research where an experiment can not be conducted and where a researcher has to figure out that whether the two variable are in association with each other and if these are related then in what way the association between these two exists without any manipulation from the researcher's end.

It seeks to understand, measure and make assessment of the relationship or  

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3 years ago
HOW DO U FEEL WHEN U PLAY OR WATCH BADMINTON?
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Answer:

I feel exited and happy I enjoy it with my friend

6 0
3 years ago
Uma carga puntiforme de + 3,0uC é colocada em um ponto P de um campo elétrico gerado por uma partícula eletrizada com carga desc
expeople1 [14]

Responda:

1) E = 6 × 10 ^ 6NC ^ -1 2) Q = 6 × 10 ^ -5

Explicação:

Dado o seguinte:

Carga (q) = 3uC = 3 × 10 ^ -6C

Força elétrica (Fe) = 18N

Intensidade do campo elétrico (E) =?

1)

Lembre-se:

Força elétrica (Fe) = carga (q) * Intensidade do campo elétrico (E)

Fe = qE; E = Fe / q

E = 18N / (3 × 10 ^ -6C)

E = 6N / 10 ^ -6C

E = 6 × 10 ^ 6NC ^ -1

2)

Lembre-se:

E = kQ / r ^ 2

E = intensidade do campo elétrico

Q = carga de origem

r = distância de espera = 30cm = 30/100 = 0,3m

K = 9,0 × 10 ^ 9

6 × 10 ^ 6 = (9,0 × 10 ^ 9 * Q) / 0,3 ^ 2

9,0 × 10 ^ 9 * Q = 6 × 10 ^ 6 * 0,09

Q = 0,54 × 10 ^ 6 / 9,0 × 10 ^ 9

Q = 0,06 × 10 ^ (6-9)

Q = 0,06 × 10 ^ -3

Q = 6 × 10 ^ -5 = 60 × 10 ^ -6 = 60μC

7 0
3 years ago
Under state law, what is the blood-alcohol limit for legally operating a motor vehicle?
Ymorist [56]

Answer:

HOPE IT HELPS....

Explanation:

CORRECT ANSWER IS 0.08

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