Answer:
The work required to move this charge is 0.657 J
Explanation:
Given;
magnitude of charge, q = 4.4 x 10⁻⁶ C
Electric field strength, E = 3.9 x 10⁵ N/C
distance moved by the charge, d = 50 cm = 0.5m
angle of the path, θ = 40°
Work done is given as;
W = Fd
W = FdCosθ
where;
F is the force on the charge;
According the coulomb's law;
F = Eq
F = 3.9 x 10⁵ x 4.4 x 10⁻⁶ = 1.716 N
W = FdCosθ
W = 1.716 x 0.5 x Cos40
W = 0.657 J
Therefore, the work required to move this charge is 0.657 J
Answer:
(a)= 264mmHg
(b)= 2000mmHg
(c)474.82mmHg
(d)= 511.63mmHg
Explanation:
the question deals with boyles law, which states that the volume of a given mass of gas at constant temperature is inversely proportional to its pressure
V ∝ 1/P
P₁V₁ = P₂V₂
making V₂ as the subject of formular
P₂ = P₁V₁/ V₂
with a volume of 25.0L
P₂ = 660×10 / 25
= 264mmHg
with a volume of 3.30 L
P₂ = 660 × 10 / 3.30
= 2000mmHg
with a volume of 13900 mL
= 13.9L
P₂ =660× 10 / 13.9
474.82mmHg
with a volume of 12900 mL
P₂ =660×10 / 12.9
= 511.63mmHg
Answer: the external agent must do work equal to -1.3 × 10⁻⁸ J
Explanation:
Given that;
Mass M1 = 7.0 kg
r = 3.0/2 m = 1.5 m
Mass M2 = 21 kg
we know that G = 6.67 × 10⁻¹¹ N.m²/kg²
work done by an external agent W = -2GM2M1 / r
so we substitute
W = (-2 × 6.67 × 10⁻¹¹ × 21 × 7) / 1.5
W = -1.96098 × 10⁻⁸ / 1.5
W = -1.3 × 10⁻⁸ J
Therefore the external agent must do work equal to -1.3 × 10⁻⁸ J
Answer:
Naturally occurring radio waves are made by lightning or by astronomical objects. Artificially generated radio waves are used for fixed and mobile radio communication, broadcasting, radar and other navigation systems, communications satellites, computer networks and innumerable other applications.
Explanation:
Answer with Explanation:
We are given that
A.Mass,m=12 kg
Speed,v=1.5m/s
Net force in x direction must be zero
Net force in y direction
Power,P=Fv
Where 
B.Substitute the values
