¿Por qué el concepto de trabajo no es lo mismo para un mecánico y un físico? ¿Cuál es la medida de trabajo que se utiliza en el
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In the single-slit experiment, the displacement of the minima of the diffraction pattern on the screen is given by
(1)
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit
In our problem,
while the distance between the first and the fifth minima is
(2)
If we use the formula to rewrite
, eq.(2) becomes
Which we can solve to find a, the width of the slit:
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
D is the distance of the screen from the slit
a is the width of the slit
In our problem,
while the distance between the first and the fifth minima is
If we use the formula to rewrite
Which we can solve to find a, the width of the slit:
Answer:
b) TA = TB = TC
Explanation:
- When put in contact each other, and isolated, both blocks will exchange heat till they reach to thermal equilibrium.
- During this process, the body at a higher temperature, will loss heat, tat it will be gained by the other body.
- The equilibrium condition will be reached when the following equation be met:
- Replacing by the values of T₀A = 300º C, and T₀B = 400ºC, and simplifying common terms as mA = mB, we can solve for Tfin, as follows:
- So, when both blocks reach to equilibrium, they will be at a common final temperature, 350ºC.
- When put in contact with block C, at the same temperature, at that instant, the three blocks will have the same common temperature of 350 ºC.
- So, option b) is the right one.