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AlexFokin [52]
4 years ago
15

Which image represents the force on a positively charged particle caused by an approaching magnet?

Physics
1 answer:
Elenna [48]4 years ago
4 0
D I think opposite is negative towards positive if I remember
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A displacement vector is 34.0 m in length and is directed 60.0° east of north. What are the components of this vector? Northward
PolarNik [594]

Answer:

A)  29.4 m 17.0 m; B) 2 m

Explanation:

If a vector is 34.0 m in length and is directed 60.0° east of north (which means 30.0° over the horizontal), then its coordinates will be:

Horizontal: (34.0 m)cos(30.0°)=29.4 m

Vertical: (34.0 m)sin(30.0°)=17 m

If one person walks 8.0 meters in a straight line and then walks 5.0 meters in another straight line, then the minimum displacement would be to go back over his tracks, displacing himself 8m-5m=3m, while the maximum displacement would be going straight ahead, displacing himself 8m+5m=13m. Any answer outside this interval is impossible (2m).

8 0
3 years ago
Draw Graph for the derivation of three equations of Motion​
Over [174]

Answer:

Hey mate I shall not tell you the answer I shall explain it to you after this if still you can't understand then say

Explanation:

Derive v = u + at by Graphical Method. Consider the velocity – time graph of a body shown in the below Figure

Derive s = ut + (1/2) at2 by Graphical Method. Velocity so time graph to derive the equations of motion.

Derive v2 = u2 + 2as by Graphical Method. Velocity–Time graph to derive the equations of motion.

I hope you understand now

enjoy your day

#Captainpower :)❤❤

5 0
3 years ago
Use the dimensional analysis and check the correctness of given equation:-<br> PV= nRT
Harman [31]

PV=nRT

Here

P=Pressure

V=Volume

n=Molarity

R=universal gas constant

T=Temperature.

LHS

\\ \tt\bull\leadsto PV

\\ \tt\bull\leadsto [ML^2T^{-2}][M^0L^3T^0]

\\ \tt\bull\leadsto [ML^5T^{-2}]

RHS

\\ \tt\bull\leadsto nRT

\\ \tt\bull\leadsto [M^0L^{3}T^0][M^1 L^2 T^{-2}K^{-1}][M^0L^0T^0K^1]

\\ \tt\bull\leadsto [ML^5T^{-2}]

LHS=RHS

hence verified

6 0
3 years ago
What is the energy range (in joules) of photons of wavelength 410 nm to 750 nm ? Express your answers using two significant figu
andreyandreev [35.5K]

Answer:

4.9 x 10^-19 J, 2.7 x 10^-19 J

Explanation:

first wavelength, λ1 = 410 nm = 410 x 10^-9 m

Second wavelength, λ2 = 750 nm = 750 x 10^-9 m

The relation between the energy and the wavelength is given by

E = h c / λ

Where, h is the Plank's constant and c be the velocity of light.

h = 6.63 x 10^-34 Js

c = 3 x 10^8 m/s

So, energy correspond to first wavelength

E1 = (6.63 x 10^-34 x 3 x 10^8) / (410 x 10^-9) = 4.85 x 10^-19 J

E1 = 4.9 x 10^-19 J

So, energy correspond to second wavelength

E2 = (6.63 x 10^-34 x 3 x 10^8) / (750 x 10^-9) = 2.652 x 10^-19 J

E2 = 2.7 x 10^-19 J

4 0
3 years ago
A exaplme of a spoiler in flight <br>​
Degger [83]

Answer:bad?

Explanation:

3 0
3 years ago
Read 2 more answers
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