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Nataliya [291]
4 years ago
6

Which of the following is an example of a pull?

Physics
1 answer:
Alenkasestr [34]4 years ago
4 0
D, because you are pulling on the rope. :)
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2 years ago
A particle with charge -5.60 nC is moving in a uniform magnetic field →B=−(1.25T) k The magnetic force on the particle is measur
chubhunter [2.5K]

Answer:

Explanation:

Force = q ( v x B)

- 5.6 x 10⁻⁹ (v x - 1.25 k )

- 3.4x 10⁻⁷i + 7.4 x 10⁻⁷j

Let v = ai+bj +ck

Force = - 5.6 x 10⁻⁹ [(ai+bj +ck) x - 1.25 k )]

= - 5.6 x 10⁻⁹ ( 1.25aj - 1.25bi )

= - 7 a j + 7 b i

( 7bi - 7aj ) x 10⁻⁹

Comparing with given force

7b x 10⁻⁹ b = - 3.4 x 10⁻⁷

b = - 48.57

- 7 a x 10⁻⁹ = 7.4 x 10⁻⁷

a = - 105.7

velocity

= -105.7 i - 48.57 j + ck

b ) Component along k can not be obtained .

c ) v . F = ( -105.7 i - 48.57 j + ck ) . −(3.40×10−7N) ˆı +(7.40×10−7N) ˆȷ

= 105.7 x 3.4 x 10⁻⁷ - 48.57 x 7.4 x 10⁻⁷

= 359.38 x 10⁻⁷ - 359.38 x 10⁻⁷

=0

angle between v and F = 90 degree

4 0
3 years ago
The ray model of light states that light travels in the form of ?
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Electromagnetic waves
4 0
3 years ago
The magnitude of the force associated with the gravitational field is constant and has a value f. A particle is launched from po
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The particle will have an energy of 12U0. A particle travels at an initial velocity from point B to point A, gaining U0 joules of kinetic energy along the way. The constant force at this point is equal to 12F.

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6 0
1 year ago
At a distance of 41 ft , an ionizing radiation source delivers 5.0 rem of radiation. How close could you get to the source and s
mash [69]

Answer:

at distance 18.33 ft no biological effects

Explanation:

given data

distance = 41 ft

radiation = 5 rem

to find out

how close get so no biological effects

solution

we know here that intensity of radiation R is inversely proportional to (radiation)²

so here equation will be

\frac{I1}{I2}  = (\frac{R2}{R1})^{2}   .............1

here I is intensity

so here I1 = 25

because for  0 to 25 there is  no detectable effects and for 25 to 100 it will . temporary decrease so

we take 25 because dose is less than 25 so we take that highest value

so

\frac{I1}{I2}  = (\frac{R2}{R1})^{2}

\frac{25}{5}  = (\frac{41}{R1})^{2}

R1 = 18.33 ft

so at distance 18.33 ft no biological effects

6 0
3 years ago
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