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vagabundo [1.1K]
3 years ago
12

What are the causes of season change in the earth​

Physics
2 answers:
almond37 [142]3 years ago
5 0

Answer:

the causes of season change on the earth is due to the tilted axis

fredd [130]3 years ago
4 0

Answer:

Earth's tilted axis causes the seasons.

Explanation:

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Tju [1.3M]

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if i was to have a 10kg toy car and it was moving away from you it would get smaller like you was backing up.

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velocity means speed-

not for sure im new here so sorry if i'm wrong  

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4. AN OBJECT INCREASES ITS VELOCITY
Cloud [144]

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it is accelerating 14 m/s

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Clear cutting has a similar effect as controlled burning of a forest. <br><br> True<br><br> False
mariarad [96]
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3 years ago
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What is the level of incidence
-Dominant- [34]

Answer:

The incidence rate is typically expressed as the number of cases per person-year of observation. Only new cases are considered when computing the incidence rate, while cases that were diagnosed earlier are excluded. The “population at risk” measure is usually obtained from census data.

Explanation:

The incidence rate is typically expressed as the number of cases per person-year of observation. Only new cases are considered when computing the incidence rate, while cases that were diagnosed earlier are excluded. The “population at risk” measure is usually obtained from census data.

5 0
3 years ago
A wheel rotates with a constant angular acceleration of  rad/s2. During a certain time interval its angular displacement is  r
Hatshy [7]

Answer:

The angular velocity at the beginning of the interval is \pi\sqrt{2}\ rad/s.

Explanation:

Given that,

Angular acceleration \alpha=\pi\ rad/s^2

Angular displacement \theta=\pi\ rad

Angular velocity \omega =2\pi\ rad/s

We need to calculate the angular velocity at the beginning

Using formula of angular velocity

\alpha =\dfrac{\omega^2-\omega_{0}^2}{2\theta}

\omega_{0}^2=\omega^2-2\alpha\theta

Where, \alpha = angular acceleration

\omega = angular velocity

Put the value into the formula

\omega_{0}^2=(2\pi)^2-2\times\pi\times\pi

\omega=\sqrt{2\pi^2}

\omega_{0}=\pi\sqrt{2}\ rad/s

Hence, The angular velocity at the beginning of the interval is \pi\sqrt{2}\ rad/s.

3 0
3 years ago
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