Question

what is the force on a 1000 kilogram -elevator that is falling freely under the accerleration of gravity only (9.8m/s2)?

Answer 1

Answer:

$W = 9800 \ \rm N.$

Explanation:

Given data:

Mass, $m = 1000 \ kg$

Acceleration due to gravity, $g = 9.8 \ m/s^{2}$

Here, the elevator is in free-fall. The force experienced by the elevator would be equal to its weight.

Thus,

$W = mg$

$W = 1000 \ kg \times 9.80 \ m/s^{2}$

$W = 9800 \ \rm N.$