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Leto [7]
3 years ago
14

 You are at an office party, a holiday party, or a gathering of friends at the home of a neighbor and you are engaged in convers

ation with a friend in a discussion. More people are talking behind you, but you are not paying attention to their conversation. Suddenly, you hear your name mentioned by one of the individuals engaged in the conversation behind you. You become unable to concentrate on the discussion, because you are too busy trying to hear what the other people are saying about you. You know you were not deliberately eavesdropping on this conversation, but you know that you heard your name. Is it possible that you were unconsciously eavesdropping?
 
​
Physics
1 answer:
irina [24]3 years ago
3 0

The correct answer is; Yes, you can be unconsciously eavesdropping.

Further Explanation:

When this occurs it is called the “The Cocktail Party Phenomenon.” Your mind can focus on one conversation that is being made and drown out all other speech and things going on around you. This makes your brain have auditory attention on one specific conversation.

The sensory hearing in the person listening to the conversation is subconsciously filtering the conversation into its own stream in the brain. This phenomenon can also detect certain words that are important to the person with a large amount of noise in the background.

This occurs in the left hemisphere of the brain in the superior temporal gyrus region.

Learn more about the Cocktail Party Phenomenon at brainly.com/question/14532863

#LearnwithBrainly

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You drop a rock into a pond, and water waves spread out in circles. (a) The waves carry water outward, away from where the rock
coldgirl [10]

Answer:

Explanation:

wave motion is defined as the propagation of the disturbance due to continous vibration of the molecules of the medium. Waves oduced due to disturbance carry only energy but not the matter.

The waves move water up and down and carry the energy.

Therefoe, the statement "(a) The waves carry water outward away from where the rock hit. The moving water carries energy outward"is incorrect.

The waves move water up and down and carry the energy, but not matter.

Therefore, the statement "(c) The waves ony make the water move u and down. No energy is carried outward from where the rock hit" is incorrect.

When a rock is droed ito a pd, a disturbance starts from the point where the stone hits the water. The waves produced carry the energy from the starting point toother locatons over a large distance which is not possible by the single molecules of water.

Therefore, the statement "(c) The waves only make the water move up and down, but the waves do carry energy outward away from where the rock hit" is correct.

4 0
3 years ago
Two waves have the same amplitude and are traveling through the same medium, but the first wave has a higher frequency. The ener
iris [78.8K]
Your answer is True!
8 0
3 years ago
A string is waved up and down to create a wave pattern with a wavelength of 0.5 m. If the waves are generated with a frequency o
Pachacha [2.7K]

Answer:

1m/s

Explanation:

Speed of a wave is expressed as;

Speed = frequency × wavelength

Given

Frequency = 2Hz

Wavelength = 0.5m

Required

Speed of the wave

Substitute

Speed = 2×0.5m

Speed = 1.0m/s

Hence the speed is 1.0m/s

6 0
3 years ago
A thin rod (length = 2.97 m) is oriented vertically, with its bottom end attached to the floor by means of a frictionless hinge.
nlexa [21]

Answer:

a)  w = 2.57 rad / s , b)   α = 3.3 rad / s²

Explanation:

a) Let's use the conservation of mechanical energy, we will write it in two points the highest and when touching the ground

Initial. Higher

       Em₀ = U = m g h

Final. Touching the ground

       Em_{f} = K = ½ I w²

How energy is conserved

       Em₀ = Em_{f}

       mg h = ½ I w2

The moment of specific object inertia

        I = m L²

We replace

       m g h = ½ (mL²) w²

       w² = 2g h / L²

The height of the object is the length of the bar

        h = L

        w = √ 2g / L

       w = √ (2 9.8 / 2.97)

       w = 2.57 rad / s

b) the angular acceleration can be found from Newton's second rotational law

       τ = I α

       W L = I α

       mg L = (m L²) α

       α = g / L

       α = 9.8 / 2.97

       α = 3.3 rad / s²

3 0
3 years ago
When you jump, you push down on the earth and it pushes back up against you. The earth pushing up against you is what causes you
MissTica

That's a great question !

The answer is:<em> It does !</em>

A push on an object causes the object to <u><em>accelerate</em></u> in the direction of the force.  

The <em>less</em> mass the object has, the <em>more</em> the force accelerates it.

Now, when you jump, the forces on you and on the Earth are equal forces.

The up force on you causes you to accelerate up by some amount.

The down force on the Earth causes the Earth to accelerate down by some amount.

The Earth's mass is something like 5,972,000,000,000,000,000,000,000 kg, while your mass is something like 50 kg.

The Earth has something like 119,400,000,000,000,000,000,000 <em>times</em> as much mass as you have.

So your acceleration is something like 119,400,000,000,000,000,000,000 <em>times as great as the Earth's acceleration.</em>

==> The Earth's downward acceleration, caused by your jump, is there.  It's just too small to notice.

<em>BUT . . .</em> That's the reason why seismometers (instruments to detect and measure the vibrations from distant earthquakes) have to be located as far as possible from cities and busy roads.

In places that are too close to cities and roads, the Earth's surface is always vibrating, wiggling, jiggling, heaving and weaving, in reaction to the forces of people walking around, cars and trucks driving around, even rain falling down.  And kids jumping up and down !  

In such places, these people-motions are louder and stronger than the vibrations coming from distant earthquakes.  Seismometers wouldn't work there.    

5 0
3 years ago
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