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3 years ago

How does the sun's energy travel to Earth?

Physics

2 answers:

Sidana [21]3 years ago

8 0

Answer:

When the Sun's energy moves through space, it reaches Earth's atmosphere and finally the surface. This radiant solar energy warms the atmosphere and becomes heat energy. This heat energy is transferred throughout the planet's systems in three ways: by radiation, conduction, and convection.

Elena-2011 [213]3 years ago

5 0

Answer: The sun’s radiation consists of small, massless packets of energy called photons. They travel seamlessly through space; whenever they strike any object, the object absorbs photons and its energy is increased, which then heats it up.

Explanation:

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Question 18 according to newton's second law of motion, the force acting on an object varies directly with the object's accelera

leonid [27]

Solve for "x"
X=force
18/6=x/9
cross multiply
162=6x
x=27
Hope this helps

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3 years ago

A 7300 N elevator is to be given an acceleration of 0.150g by connecting it to a cable of negligible weight wrapped around a tur

Firlakuza [10]

Answer:

α =18.75 rad/s²

Explanation:

Given that

Acceleration a = 0.15 g

We know that g =10 m/s²

a= 0.15 x 10 = 1.5 m/s²

d= 16 cm

Radius r= 8 cm

Lets take angular acceleration =α rad/s²

As we know that

a= α r

Now by putting the values

1.5 = α x 0.08

α =18.75 rad/s²

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3 years ago

Hurry need an answer

notsponge [240]

Answer:

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Explanation:

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3 years ago

A normal blood pressure reading is less than 120/80 where both numbers are gauge pressures measured in millimeters of mercury (m

KIM [24]

The pressure value is given by the equation,

$P= \rho gh$

Where,

$\rho$ represents the density of the liquid

g= gravity

h= Heigth

A) For the measurement of the guage pressure we have the data data,

$\rho_{mercury} = 13.6*10^3kg/m^3$

$h=0.0930m$

$g=9.8m/s^2$

Replacing we get,

$P_g=\rho_{mercury}gh$

$[tex]P_g = (13.6*10^3)(9.8)(0.0930)$ P_g = 12395Pa[/tex]

In order to find the Absolute pressure, we perform a sum between the atmospheric pressure and that of the Gauge,

B) The atmospheric pressure at sea level is 101325Pa, assuming ideal conditions, we will take this pressure for our calculation, so

$P_T = P_a+P_g\\P_T = 101325Pa+12395Pa\\P_T = 113720Pa\\P_T = 113.7kPa$

6 0

3 years ago

An argon ion laser puts out 5.0 W of continuous power at a wavelength of 532 nm. The diameter of the laser beam is 5.5 mm. If th

stepan [7]

Answer:

Number of photons travel through pin hole= $6.4*10^{17}$

Explanation:

First we will calculate the energy of single photon using below formula:

$E=\frac{h*c}{λ}$

Where :

h is plank's constant with value $6.626*10^{-34} J.s$

c is the speed of light whch is $3*10^{8}$

λ is the wave length = 532nm

$E=\frac{6.6268*10^{-34}* 3*10^{8}}{532nm}$

E= $3.73*10^{-19}$ J

Number of photons emitted per second:

$\frac{5J/s}{1 photon/3.73*10^{-19} }$

Number of photons emitted per second= $1.34*10^{19} photons/s$

$\frac{A-hole}{A-beam}$ = $\frac{\frac{pie*d-hole^2}{4}}{\frac{pie*d-beam^2}{4} }$

Where:

A-hole is area of hole

A-beam is area of beam

d-hole is diameter of hole

d-beam is diameter if beam

$\frac{A-hole}{A-beam}$ = $\frac{d-hole^2}{d-beam^2}$

$\frac{Ahole}{A-beam}$ = $\frac{1.22^2}{5.5^2}$

$\frac{A-hole}{A-beam}$ = $\frac{144}{3025}$

Number of photons travel through pin hole= $1.34*10^{19} *\frac{144}{3025}$

Number of photons travel through pin hole= $6.4*10^{17}$

7 0

2 years ago