What are the change in internal energy if 250 j of hear is added to a system of 80 j of work is done by the system
1 answer:
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Answer:
Distance = 84 meters
Explanation:
Given the following data;
Work done = 168,000 Joules
Force = 2,000 Newton
To find the distance covered by the automobile, we would use the formula;
Substituting into the formula, we have;
Distance = 84 meters
Answer:
the frequency of the oscillation is 1.5 Hz
Explanation:
Given;
mass of the spring, m = 1500 kg
extention of the spring, x = 5 mm = 5 x 10⁻³ m
mass of the driver = 68 kg
The weight of the driver is calculated as;
F = mg
F = 68 x 9.8 = 666.4 N
The spring constant, k, is calculated as;
k = F/m
k = (666.4 N) / (5 x 10⁻³ m)
k = 133,280 N/m
The angular speed of the spring is calculated;
The frequency of the oscillation is calculated as;
ω = 2πf
f = ω / 2π
f = (9.426) / (2π)
f = 1.5 Hz
Therefore, the frequency of the oscillation is 1.5 Hz