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Butoxors [25]
3 years ago
12

someone please explain how to separate copper powder from a mixture containing copper and zinc powder !!

Chemistry
1 answer:
jarptica [38.1K]3 years ago
6 0

Answer:

by burning the mixture in an electrical furnace to a temp. 640 degree C. to melt both Zinc & Aluminum leaving copper oxide as a powder.

Explanation:

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You titration 5.0 mL of HCl with 0.010 M NaOH. You find the end point of your titration occurs when 12.0 mL of NaOH has been add
Nookie1986 [14]

your answer is 0.00833M the volume was converted into liters

NaOH(aq)+HCl(aq)→NaCl(aq)+H2O(l)

Using the molarity equation, we can find the number of moles of HCl that reacted:

molarity=mol soluteL soln

mol solute=(molarity)(L soln)

mol HCl=(0.105molL)(0.0250L)=0.00263 mol HCl

(volume converted to liters)

Now, using the coefficients of the chemical reaction, we can determine the number of moles of NaOH that reacted:

0.00263mol HCl(1lmol NaOH1mol HCl)=0.00263 mol NaOH

Lastly, we'll use the molarity equation (using given volume of NaOH soln) again to determine the molarity of the sodium hydroxide solution:

molarity=mol soluteL soln

5 0
3 years ago
Arsenic(III) sulfide sublimes readily, even below its melting point of 320 °C. The molecules of the vapor phase are found to eff
dezoksy [38]

The molecular formula : As₄S₆

<h3>Further explanation</h3>

Given

Rate of effusion of arsenic(III) sulfide = 0.28 times the rate of effusion of Ar atoms

Required

The molecular formula

Solution

Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or  

the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

or  

\rm M_1\times r_1^2=M_2\times r_2^2

Input the value :

1 = Arsenic(III) sulfide

2 = Ar

MM Ar = 40 g/mol

0.28 = √(40/M₁)

M₁=40 : 0.28²

M₁=510 g/mol

The empirical formula of arsenic(III) sulfide =  As₂S₃

(Empirical formula)n = molecular formula

( As₂S₃)n = 510 g/mol

(246.02 g/mol)n = 510 g/mol

n = 2

So the molecular formula : As₄S₆

5 0
3 years ago
If you need to reverse the following reaction in order for it to be an intermediate reaction in a Hess's law problem, what would
Olin [163]
When reversing a given reaction, we simply change the sign of the standard enthalpy change value. Therefore, the reaction will become:
H₂O → H₂ + 0.5O₂, ΔH = 286kJ
This is because if a certain amount of energy is released when a reaction occurs, the same amount of energy must be supplied for the reaction to occur in the reverse direction.
4 0
3 years ago
Read 2 more answers
What is defined as the absorption of oxygen and the release of carbon dioxide by cells?
lara31 [8.8K]

Answer:

Cellular respiration

Explanation:

Oxygen is required by the cell in the Krebs cycle as the ultimate proton acceptor (creating water an end product during making out ATPs). During the conversion of pyruvate from glycolysis to Acetyl-CoA that enters the Krebs cycle, the pyruvate is decarboxylated (or oxidized) hence creating carbon IV oxide as a byproduct.

4 0
4 years ago
Fill in the [?]: 5,481 g = [?] lb. ​
Sophie [7]

Answer:

12.084 lb

Explanation:

1 gram = 0.00220462 lb

multiply number of grams by 0.00220462

Ex. 2000 g x 0.00220462 = 4.409 pounds

5 0
3 years ago
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