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Butoxors [25]
3 years ago
12

someone please explain how to separate copper powder from a mixture containing copper and zinc powder !!

Chemistry
1 answer:
jarptica [38.1K]3 years ago
6 0

Answer:

by burning the mixture in an electrical furnace to a temp. 640 degree C. to melt both Zinc & Aluminum leaving copper oxide as a powder.

Explanation:

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A stock solution of 1.00 M Fe2(SO4)3 is available. How many milliliters are
Andrews [41]

Answer:

375 mL

Explanation:

M1*V1 = M2*V2

M1 = 1.00 M

V1 = ?

M2 = 0.750 M

V2 = 0.500 L

1.00 M * V1 = 0.750 M * 0.500 L

V1 = 0.750*0.500/1.00 = 0.375 L = 375 mL

5 0
3 years ago
How many moles of lithium are in 18.2 grams of lithium
Doss [256]

Answer:

I think 2.6 sorry if its wrong

6 0
3 years ago
Read 2 more answers
PLEASE HELPPPPPPPPPPPPPP​
melamori03 [73]
It changes from a liquid from to a solid.

I hope this helps!
3 0
3 years ago
A 25 gram(m) metal ball is heated to 200C(delta T) with 2330 Joules(q) of energy. What is the specific heat of the metal?
Dominik [7]

Answer:

The specific heat of the metal is 0.466 \frac{J}{g*C}

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

The equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case:

  • Q= 2330 J
  • c= ?
  • m= 25 g
  • ΔT= 200 °C

Replacing:

2330 J= c*25 g* 200 °C

Solving:

c=\frac{2330 J}{25 g* 200 C}

c=0.466 \frac{J}{g*C}

<u><em>The specific heat of the metal is 0.466 </em></u>\frac{J}{g*C}<u><em></em></u>

6 0
3 years ago
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Sulfur and oxygen form both sulfur dioxide and sulfur trioxide. When samples of these are decomposed, the sulfur dioxide produce
Diano4ka-milaya [45]
To determine the mass of oxygen per gram of sulfur for sulfur dioxide, we simply obtain the ratio of the mass of oxygen and the mass of sulfur produced from the decomposition of sulfur dioxide. All other values given in the problem statement above are just to confuse us that the question is a difficult one. We do as follows:

mass of oxygen per gram sulfur = 3.45 g / 3.46 g
mass of oxygen per gram sulfur = 0.9971 g O2 / g S
4 0
3 years ago
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