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Leto [7]
4 years ago
15

Please answer ASAP! Where on the Periodic Table are Transition Elements located?

Chemistry
1 answer:
igor_vitrenko [27]4 years ago
6 0

c group A is the correct answer

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(copied from last question and fixed) (there's three question so triple points)
hammer [34]

Question 1: A

Question 2: B

Question 3: B

7 0
3 years ago
The idea that an emotion-arousing stimulus is simultaneously routed to the cortex and to the sympathetic nervous system is centr
pshichka [43]
<h3><u>Answer;</u></h3>

Cannon-Bard theory

<h3><u>Explanation</u>;</h3>
  • <em><u>The idea that an emotion-arousing stimulus is simultaneously routed to the cortex and to the sympathetic nervous system is central to the Cannon-Band theory.</u></em>
  • Cannon-Bard theory states that we feel emotions and experience physiological reactions such as sweating, trembling, and muscle tension simultaneously.
  • The theory argues that we experience physiological arousal and emotion at the same time. The theory gives more attention to the role of thought or outward behavior as compared to James-Lange.
7 0
4 years ago
Read 2 more answers
How many moles of methane are in 7.31*10^25 molecules?
GrogVix [38]
<h3>Answer:</h3>

121 mol CH₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Organic</u>

  • Writing chemical compounds
  • Writing organic structures
  • Prefixes
  • Alkanes, Alkenes, Alkynes

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

7.31 × 10²⁵ molecules CH₄

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u />\displaystyle 7.31 \cdot 10^{25} \ molecules \ CH_4(\frac{1 \ mol \ CH_4}{6.022 \cdot 10^{23} \ molecules \ CH_4} ) = 121.388 \ mol \ CH_4<u />

<u />

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

121.388 mol CH₄ ≈ 121 mol CH₄

7 0
3 years ago
Living organisms all have DNA and RNA which are both _______
ivanzaharov [21]
Both DNA and RNA are molecules that store genetic information.  
4 0
3 years ago
Read 2 more answers
The equilibrium constant, Kc, for the following reaction is 77.5 at 600 K. CO(g) Cl2(g) COCl2(g) Calculate the equilibrium conce
Margarita [4]

Answer:

[CO] = 0.078M

[Cl2] = 0.078M

[COCl2] = 0.477M

Explanation:

Based on the reaction:

CO(g) Cl2(g) ⇄ COCl2(g)

<em>Where equilibrium constant, kc, is:</em>

kc = 77.5 = [COCl2] / [CO] [Cl2]

[] represents the equilibrium concentration of each gas. The initial concentration of each gas is:

[CO] = 0.555mol/1.00L = 0.555M

[Cl2] = 0.555M

And equilibrium concentrations are:

[CO] = 0.555M - x

[Cl2] = 0.555M - x

[COCl2] = x

<em>Where x is reaction coordinate</em>

Replacing in kc expression:

77.5 = [x] / [0.555M - x] [0.555M - x]

77.5 = x / 0.308025 - 1.11 x + x²

23.8719 - 86.025 x + 77.5 x² = x

23.8719 - 87.025 x + 77.5 x² = 0

x = 0.477M. Right answer

x = 0.646M. False answer. Produce negative concentrations

Replacing:

<h3>[CO] = 0.555M - 0.477M = 0.078M</h3><h3>[Cl2] = 0.078M</h3><h3>[COCl2] = 0.477M</h3>

And those concentrations are the equilibrium concentrations

6 0
3 years ago
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