1.make an observation
2.form a question
3.form a hypothesis
4.conduct an experiment
5.analyse data and draw conclusion
Answer:
0.08
Explanation:
this problem assume that both of whale and submarine are in rest position or in constant linier motion in same direction and same speed.
The sound will travel from Submarine to the whale and back again to submarine. so the time will be like this
t = 2d/v
t = 2*58.8/1520
t = 117.6/1520
t = 0.077368 s
t ≈ 0.08 s (less then 1 s)
T is in seconds (s)
<span>2pi is dimensionless </span>
<span>L is in meters (m) </span>
<span>g is in meters per second squared (m/s^2) </span>
<span>so you can write the equation for the period of the simple pendulum in its units... </span>
<span>s=sqrt(m/(m/s^2)) </span>
<span>simplify</span>
<span>s=sqrt(m*s^2*1/m) cancelling the m's </span>
<span>s=sqrt(s^2) </span>
<span>s=s </span>
<span>therefore the dimensions on the left side of the equation are equal to the dimensions on the right side of the equation.</span>
Answer:
1.25 m
Explanation:
From the question given above, the following data were obtained:
Force ratio = 2.5
Distance of load from the fulcrum = 0.5 m
Distance of effort =.?
The distance of the effort from the fulcrum can be obtained as illustrated below:
Force ratio = Distance of effort / Distance of load
2.5 = Distance of effort / 0.5
Cross multiply
Distance of effort = 2.5 × 0.5
Distance of effort = 1.25 m
Therefore, the distance of the effort from the fulcrum is 1.25 m
