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sweet-ann [11.9K]
3 years ago
8

The ability of an element to react is the elements

Chemistry
1 answer:
Softa [21]3 years ago
6 0
B activity is the answer
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1. (Physical or Chemical) properties describe matter.
antoniya [11.8K]

Explanation:

2. Chemical

3. Physical

5. Chemical

I think that's it

Hope it helps :)

8 0
3 years ago
Jeffry was wondering why when he made breakfast, that after he was done cooking, the mass of everything he used was not the same
12345 [234]

Answer:

equivalent exchange forces cancel out but the  substances are affected around the area

Explanation:

4 0
2 years ago
The reaction converting glycerol to glycerol-3-phosphate can be represented as: glycerol + hpo42− ⟶ glycerol-3-phosphate + h2o.
Volgvan

Answer;

Yes; this reaction be spontaneous if coupled with the hydrolysis of ATP.

Explanation;

The reaction converting glycerol to glycerol-3-phosphate (energetically unfavorable) can be coupled with the conversion of ATP to ADP (energetically favorable):

Glycerol + HPO42 ⟶glycerol-3-phosphate+H2O

ATP + H2O⟶ ADP + HPO42− + H+

6 0
3 years ago
Read 2 more answers
Chloroform is a liquid once used for anesthetic. What is the volume of 5.0 g of chloroform? The density of chloroform 1.49 g/mL
mario62 [17]

Answer:

3.3557047 mL

Explanation:

The density can be found using the following formula:

d=\frac{m}{v}

Let's rearrange the formula to find the volume, v.

d*v=\frac{m}{v}*v

d*v=m

\frac{d*v}{d} =\frac{m}{d}

v=\frac{m}{d}

The volume can be found by dividing the mass by the density. The mass of the chloroform is 5 grams and the density is 1.49 grams per milliliter. Therefore,

m= 5g \\d= 1.49 g/mL

Substitute the values into the formula.

v=\frac{5g}{1.49 g/mL}

Divide. When we divide, the grams, or g, in the numerator and denominator will cancel out.

v= \frac{5}{1.49}mL

v=3.3557047 mL

The volume of 5 grams of chloroform is 3.3557047 milliliters

4 0
3 years ago
Pls help me I have 5 mins Science is a unique field of thought because it relies on _______ to describe the world
Pani-rosa [81]
Most reasonable answer:
Observations and experimentation
5 0
3 years ago
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