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KatRina [158]
3 years ago
10

What changes to landforms are caused by movements at transform boudaries

Physics
1 answer:
I am Lyosha [343]3 years ago
4 0
Not much changes, but there are some great pressure so some hills may form. 
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(03.05 LC)<br> Which of the following best describes the use of a renewable resource
RUDIKE [14]

Answer:

Option C or the third option.

Explanation: Water is a renewable resource there is so much of it and it just keeps circulating through the system it doesn't run out.

6 0
3 years ago
Cole is riding a sled with initial speed of 5 m/s from west to east. the frictional force of 50 n exists due west. the mass of t
stepan [7]
We can calculate the acceleration of Cole due to friction using Newton's second law of motion:
F=ma
where F=-50 N is the frictional force (with a negative sign, since the force acts against the direction of motion) and m=100 kg is the mass of Cole and the sled. By rearranging the equation, we find
a= \frac{F}{m}= \frac{-50 N}{100 kg}=-0.5 m/s^2

Now we can use the following formula to calculate the distance covered by Cole and the sled before stopping:
a= \frac{v_f^2-v_i^2}{2d}
where
v_f=0 is the final speed of the sled
v_i=5 m/s is the initial speed
d is the distance covered

By rearranging the equation, we find d:
d= \frac{v_f^2-v_i^2}{2a}= \frac{-(5 m/s)^2}{2 \cdot (-0.5 m/s^2)}=25 m
3 0
3 years ago
I run around a circular track, with radius 25m, for 4 and times before stopping. It takes me 16
Sergio039 [100]

Answer:

13m/s. is the answer probably but do u have ms gallup too?

4 0
2 years ago
A seismographic station receives S and P waves from an earthquake, separated in time by 17.8 s. Assume the waves have traveled o
Georgia [21]

Answer:

D = 230.2 Km

Explanation:

let distance between seismograph and focus of quake is D

From time distance formula we  can calculate the time taken by the S wave

T_1 =\frac{D}{4.5}

From time distance formula we  can calculate the time taken by the P wave

T_2 =\frac{D}{6.90}

It is given in equation both waves are seperated from each other by 17.8 sec

so we have

T_1 - T_2 = 17.8sec

Putting both time value to get distance value

\frac{D}{4.5} - \frac{D}{6.90} = 17.8

D = 230.2 Km

8 0
3 years ago
A roller coaster has a "hump" and a "loop" for riders to enjoy (see picture). The top of the hump has a radius of curvature of 1
nikklg [1K]

Answer:

Part a)

F_n = 306 N

Part B)

v = 12.1 m/s

Explanation:

Part A)

At the top of the hump the force on the rider is

1) Normal force

2) weight

so here we know that

mg - F_n = \frac{mv^2}{R}

F_n = mg - \frac{mv^2}{R}

F_n = (100)(9.81) - \frac{100(9^2)}{12}

F_n = 306 N

Part B)

At the top of the loop we will have

F_n + mg = \frac{mv^2}{R}

in order to remain in contact the normal force must be just greater than zero

so we will have

mg = \frac{mv^2}{R}

v = \sqrt{Rg}

v = \sqrt{15\times 9.81}

v = 12.1 m/s

5 0
3 years ago
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