Question

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Answer 1

The concentration of diluted solution is found to be 0.421 M

Explanation:

It is given that a stock solution (400 ml) should be diluted to 750 ml, we need to find the concentration of the diluted solution using the Law of Volumetric analysis,

V1M1 = V2M2

V1 being the volume of the stock solution = 400 ml

M1 being the molarity of the stock solution = 0.789 M

V2 being the volume of the diluted solution = 750 ml

M2 being the molarity of the diluted solution = ?

Now we have the molarity of the diluted solution by rearranging the above equation as,

M2 = $\frac{V1M1}{V2}$

Now plugin the values as,

M2 = $\frac{400 ml \times 0.789 M}{750 ml }$

     = 0.421 M

So the molarity of diluted solution is found to be 0.421 M.