Answer:
The object A will be having the greater density compared to object B.
Explanation:
It is known that density of any object is defined as the mass of any object occupying a given volume. So the ratio of mass and volume will help to determine the density of any object.
From the above equation, it can be seen that the density of any object is directly proportional to the mass of the object and inversely proportional to the volume occupied by the object.
So in the present context, the mass of objects A and B are same and it is 100 g. Thus, the density of object A and object B will be influenced by their volume. As it is given that the volume of object A is 50 cm3 and object B is 100 cm3, then depending upon the relationship of volume and density, the density of both the objects can be determined. As the object with higher volume will be having lesser density as volume is inversely proportional to density. Thus, in the given case the volume of object B is greater than object A and so the object A will be having greater density compared to object B.
Answer:
the option e is correct I think
The solution is either saturated or supersaturated with solute
Molar Mass and Avogadro's constant
Explanation:
- Molar mass is calculated by using the mass chemical compound, and the amount of substance. So, to find the molar mass of a particular element or the compound, we have to divide the mass of the given chemical compound or the chemical element( grams) by amount of substance ( moles).
- We can add the standard atomic mass (g/mole) of constituent atoms to find the molar mass of the compound.
- To convert atoms to molecules, we have to dive the number of atoms by Avogadro constant which is 6.022 x 10^23.
Answer:
b) warming up a) wavelength a) blank c) sample
Explanation:
<em>To run a spectrophotometry experiment, begin by </em><em>warming up</em><em> the spectrophotometer and preparing the samples.</em> It is important that the equipment is warmed up for at least 30 minutes before starting the measurements.
<em>Be sure to select the correct </em><em>wavelength</em><em>, then run a measurement on the </em><em>blank</em><em> solution.</em> The selected wavelength depends on the analyte of interest. The black solution contains the same matrix but it doesn´t contain the analyte.
<em>Follow up by running measurements on </em><em>sample</em><em> solutions. Once data is collected, turn off the instrument, clean the area, and discard the samples. </em>The samples are those of unknown concentration that we want to determine.
<u>Answer:</u> The equilibrium concentration of chloride ions in the solution is 4.532 M
<u>Explanation:</u>
We are given:
Initial molarity of = 0.054 M
Initial molarity of HCl = 4.60 M
Equilibrium molarity of = 0.034 M
The chemical equation for the reaction of and HCl follows:
Or,
<u>Initial:</u> 0.054 4.60
<u>At eqllm:</u> 0.054-x 4.60-2x x 6x
Evaluating the value of 'x':
So, equilibrium concentration of = (4.60 - 2x) = [4.60 - 2(0.034)] = 4.532 M
Hence, the equilibrium concentration of chloride ions in the solution is 4.532 M