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3 years ago

13

how could a person easily tell which letters had four and which rive pages without opening the envelope? what assumptions did yo

u make

1 answer:

Lubov Fominskaja [6]3 years ago

5 0

Had 4 what and when you said rive did u mean 5

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Which warning sign suggests being bullied?

Vikentia [17]

Answer:

when you tell someone over and over to stop bothering you and they dont so i think you should tell a teacher

Explanation:

6 0

3 years ago

The speed of a wave is 40 m/s. If the wavelength is 80 centimeters, what is the frequency of the wave?

Vedmedyk [2.9K]

<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

The speed of a wave is 40 m/s. If the wavelength is 80 centimeters, what is the frequency of the wave ?

<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>

<h3>Given:-</h3>

Velocity (V) = 40 m/s

Wavelength $(\lambda)$ = 80 cm = 0.8 m

<h3>To Find:-</h3>

The frequency (F) of the wave.

<h2>Solution:-</h2>

We know,

$\bf V \: = \: F \: × \: \lambda$

40 = F × 0.8

F = $\frac{40}{0.8}$

F = 50

<h3>The frequency of the wave is <u>5</u><u>0</u><u> </u><u>H</u><u>z</u>. [Answer]</h3>

7 0

3 years ago

5. A cheetah with a mass of 70 kg was clocked running at 72 mph (32 m's). How many joules of

blsea [12.9K]

Answer:

Kinetic energy = 35840 Joules

Explanation:

Given the following data;

Mass = 70kg

Velocity = 32m/s

To find the kinetic energy;

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

$K.E = \frac{1}{2}MV^{2}$

Where, K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

$K.E = \frac{1}{2}MV^{2}$

Substituting into the equation, we have;

$K.E = \frac{1}{2}*70*32^{2}$

$K.E = \frac{1}{2}*70*1024$

$K.E = 35 * 1024$

K.E = 35840 Joules.

Therefore, the kinetic energy possessed by the cheetah is 35840 Joules.

7 0

3 years ago

A light bulb emits light uniformly in all directions. The average emitted power is 150.0 W. At a distance of 5 m from the bulb,

beks73 [17]

Answer:

a) 0.477 W/m²

b) 13.407 N/C

c) 18.96 N/C

Explanation:

P = Power = 150 W

r = Distance = 5 m

ε₀ = Permittivity of space = 8.854×10⁻¹² F/m

a) Average intensity

$\bar{S}=\frac{P}{A}\\\Rightarrow \bar{S}=\frac{150}{4\pi r^2}\\\Rightarrow \bar{S}=\frac{150}{4\pi 5^2}\\\Rightarrow \bar{S}=0.477\ W/m^2$

∴ Average intensity is 0.477 W/m²

b) Rms value

$\bar{S}=c\epsilon_0E_{rms}^2\\\Rightarrow E_{rms}=\sqrt{\frac{\bar{S}}{c\epsilon_0}}\\\Rightarrow E_{rms}=\sqrt{\frac{\bar{0.477}}{3\times 10^8\times 8.854\times 10^{-12}}}\\\Rightarrow E_{rms}=13.407\ N/C$

∴ Rms value of the electric field is 13.407 N/C

c) Peak value

$E_0=\sqrt 2E_{rms}\\\Rightarrow E_0=\sqrt 2\times 13.407\\\Rightarrow E_0=18.96\ N/C$

∴ Peak value of the electric field is 18.96 N/C

8 0

3 years ago

Water towers store water above the level of consumers for times of heavy use, eliminating the need for high-speed pumps. How hig

Salsk061 [2.6K]

Answer:

So height will be 47.387 m

Explanation:

We have given gauge pressure $P=4.63\times 10^5N/m^2$

Density of water $\rho =997kg/m^3$

Acceleration due to gravity $g=9.8m/sec^2$

We know that pressure is given as $P=\rho gh$

$4.63\times 10^5=997\times 9.8\times h$

$h=47.387m$

So height will be 47.387 m

4 0

3 years ago