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Svetlanka [38]
3 years ago
12

Which one of the following is an incorrect representation of the indicated particle or nucleus?

Chemistry
1 answer:
Alona [7]3 years ago
6 0

Answer:

C

Explanation:

helium-3: He

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Rate is related to?<br> A. Volume<br> B. Time<br> C. Distance <br> D. Percentage
Inga [223]
I would say B. Time 
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6 0
3 years ago
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If 200 g of benzoyl peroxide are used with 38 Kg of PTFE monomer, calculate the expected molecular weight of the polymer if (i)
den301095 [7]

Explanation:

The molecular weight of benzoyl peroxide is 242.23 g/mol.

Therefore, number of moles present in 200 g of benzoyl peroxide are as follows.

            No. of moles = \frac{mass}{\text{molar mass}}

                                  = \frac{200 g}{242.23 g/mol}

                                  = 0.825 mol

Molecular weight of PTFE is 100 g/mol.Hence, calculate the number of moles of PTFE in 38 kg as follows.

As 1 kg = 1000 g. So, 38 kg = 38000 g.

             No. of moles = \frac{mass}{\text{molar mass}}

                                  = \frac{38000 g}{100 g/mol}

                                  = 380 mol

As it is given that the initiator is 15% active. So, actual number of moles of benzoyl peroxide are as follows.

                        0.15 \times 0.826

                           = 0.124 mol

For combination, 1 mol of benzoyl peroxide produces 1 chain. Therefore, degree of polymerization will be calculated as follows.

                    DP = \frac{380 mol}{0.124 mol}    

                          = 3065.33 mol

Average molecular weight of monomer is as follows.

       \frac{0.124}{0.124 + 380} \times MW_{benzoyl} + \frac{380}{0.124 + 380} \times MW_{PTFE}

       = 100.05 g/mol

Therefore, calculate the expected molecular weight of polymer as follows.

                   3065.33 \times 100.05 g/mol

                     = 306675.23 g/mol

Hence, for disproportion 1 mole benzoyl peroxide produces 2 chains.

                     DP = \frac{2 \times 380}{0.124}

                           = 6129.03

Therefore, calculate the expected polymer weight as follows.

                     6129.03 \times 100.05

                   = 613209.68 g/mol

Thus, we can conclude that the the expected polymer weight is 613209.68 g/mol.

6 0
3 years ago
1.)Which is the correct order of the organization of the human body?
Darina [25.2K]
Answers:
1. A
2. D
3. B
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3 years ago
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How many grams are in 8.2 x 1022 molecules of N216?
hoa [83]

Answer:

N2I6 = 789 g

N2I6 = 8.2x1022 molecules N2I6 x 1 mole/6.02x1023 molecules = 1.36x10-1 moles = 0.136 moles

N2I6=0.136molesx789g/mole=107g=110g

----------------------

Hope this helps, have a BLESSED AND WONDERFUL DAY!

- Cutiepatutie ☺❀❤

7 0
3 years ago
Drag each label to the correct location on the table.
AleksAgata [21]

Explanation:

1) Boyle's Law: This law states that pressure is inversely related to the volume occupied by the gas at constant temperature and number of moles.

P\propto \frac{1}{V}     (At constant temperature and number of moles)

  • When the size of the chamber is increased the volume occupied the gas will increase with which pressure exerted by the gas will decrease down.
  • When we press the inflated balloon the pressure on the gas is increased with which volume of the occupied by the gas inside the balloon decreased.

2) Charles' Law: This law states that volume occupied by the gas is directly related to the temperature of the gas at constant pressure and number of moles.

V\propto T    (At constant pressure and number of moles)

  • The size of the balloon deceases because the in winters the temperature decreases with which volume of the gas present in the balloon also decreases.
  • When the flexible closed container is heated the temperature of the gas inside the container increases with which the volume occupied by the gas in the container will increase resulting in expanding of container.

3) Avogadro's Law: This law states that volume occupied by the gas is directly related to the number of moles of the gas at constant pressure and temperature.

V\propto n   (At constant temperature and pressure)

When we blow air into the balloon the umber of air particles increases with which the volume of the gas inside the balloon also increases resulting in increase in size of the balloon.

3 0
3 years ago
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