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3 years ago

What is the period of a wave if the wavelength is 100 m and the speed is 200 m/s?

2 answers:

galina1969 [7]3 years ago

4 0

Uh it's c) 0.5 :), and for some reason i need to write 20 characters to explain it well, okay you need to divide speed/wavelength, that's it

Mumz [18]3 years ago

4 0

It's 0.5 I thought it was 2 but I was wrong it's 0.5

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Sammy feels an ocean breeze as he plays volleyball at the beach. Why do ocean winds or sea breezes blow toward shore during the

DedPeter [7]

The heat coming from the sun warms the land more quickly than the sea. As a result of these, the air near the land warm up and rises and the cooler air from the sea moves in to replace the risen air. The correct answer is option A

There will be heat transfer from a region of higher temperature to the region of lower temperature. But in the case of land and sea breeze, the transfer of heat are the result of convectional current in nature. Because the land is a better absorber of heat and also has a lower specific heat capacity compare to sea, during the day, the heat coming from the sun warms the land more quickly than the sea. As a result of these, the air near the land warm up and rises.

The cooler air from the sea moves in to replace the risen air.

Why do ocean winds or sea breezes blow toward shore during the day ? It is because air over the beach heats up, rises and is replaced by ocean air.

Therefore, option A is correct

Learn more here : brainly.com/question/1114842

4 0

3 years ago

What is the acceleration of a 10 kg mass pushed by a 5 N force

hichkok12 [17]

Answer:

The formula is a = F m so in this case a = 5 10 = 0.5 m s 2

Explanation:

3 0

2 years ago

n electromagnetic wave in vacuum has an electric field amplitude of 611 V/m. Calculate the amplitude of the corresponding magnet

enot [183]

Answer:

The corresponding magnetic field is

Explanation:

From the question we are told that

The electric field amplitude is $E_o = 611\ V/m$

Generally the magnetic field amplitude is mathematically represented as

$B_o = \frac{E_o }{c }$

Where c is the speed of light with a constant value

$c = 3.0 *0^{8} \ m/s$

$B_o = \frac{611 }{3.0*10^{8}}$

$B_o = 2.0 4 *10^{-6} \ Vm^{-2} s$

Since 1 T is equivalent to $V m^{-2} \cdot s$

$B_o = 2.0 4 *10^{-6} \ T$

6 0

4 years ago

A piano wire with mass 2.95 g and length 79.0 cm is stretched with a tension of 29.0 N . A wave with frequency 105 Hz and amplit

Romashka-Z-Leto [24]

The concept needed to solve this problem is average power dissipated by a wave on a string. This expression ca be defined as

$P = \frac{1}{2} \mu \omega^2 A^2 v$

Here,

$\mu$ = Linear mass density of the string

$\omega =$ Angular frequency of the wave on the string

A = Amplitude of the wave

v = Speed of the wave

At the same time each of this terms have its own definition, i.e,

$v = \sqrt{\frac{T}{\mu}} \rightarrow$ Here T is the Period

For the linear mass density we have that

$\mu = \frac{m}{l}$

And the angular frequency can be written as

$\omega = 2\pi f$

Replacing this terms and the first equation we have that

$P = \frac{1}{2} (\frac{m}{l})(2\pi f)^2 A^2(\sqrt{\frac{T}{\mu}})$

$P = \frac{1}{2} (\frac{m}{l})(2\pi f)^2 A^2 (\sqrt{\frac{T}{m/l}})$

$P = 2\pi^2 f^2A^2(\sqrt{T(m/l)})$

PART A ) Replacing our values here we have that

$P = 2\pi^2 (105)^2(1.8*10^{-3})^2(\sqrt{(29.0)(2.95*10^{-3}/0.79)})$

$P = 0.2320W$

PART B) The new amplitude A' that is half ot the wavelength of the wave is

$A' = \frac{1.8*10^{-3}}{2}$

$A' = 0.9*10^{-3}$

Replacing at the equation of power we have that

$P = 2\pi^2 (105)^2(0.9*10^{-3})^2(\sqrt{(29.0)(2.95*10^{-3}/0.79)})$

$P = 0.058W$

8 0

3 years ago

The force that accelerates a rocket in outer space is exerted on the rocket by the?

Nana76 [90]

Gases at pressure are released by rockets as they travel towards space. According to Newton's third law, the combustion chamber's exhaust gases push the rocket with an accelerating force known as the thrust.

<h3>Explain exactly Newton's Third Law:</h3>

According to Newton's third law, if an object A pulls on an object B, then object B must exert an equal-sized and opposite-direction force on the first thing directed in the opposite direction. This law illustrates a symmetry in nature whereby forces always occur in pairs and whereby no body can exert a force without also being subjected to one.

<h3>What are Newton's 3rd law examples?</h3>

Action and response are always equal but always move in the opposite direction, according to Newton's third law of motion. A human walking on the ground, a hammer driving a nail, a magnet attracting a paper clip, and a horse pulling a cart are all examples of Newton's third rule of motion.

To know more about Newton Third Law visit:

brainly.com/question/23772134

#SPJ4

3 0

2 years ago