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GaryK [48]
3 years ago
15

When a car burns gasoline, much of the energy is released in the form of heat. Which of the following best describes this proces

s in relation to the first law of thermodynamics?
A. Energy is not created nor destroyed, but it can change into matter.
B. Energy is not created nor destroyed, but it can change from one energy form to another.
C. Energy can be created from matter or used to produce matter.
D. Some useful energy is lost as heat whenever an energy transfer occurs.
E. Energy transfers are always 100% efficient in changing energy from one useful form to another.
Physics
1 answer:
horrorfan [7]3 years ago
7 0

Answer: Option (B) is correct.

The first law of thermodynamics is an adaptation of the law of conservation of energy, this is thoroughly adapted for the systems(thermodynamics). Law of conservation of energy defines that the total energy of a confined system is stable; energy can be transferred or converted from one form to another, but it cannot be formed or destroyed.

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How much total heat transfer is necessary to lower the temperature of 0.175 kg of steam from 125.5 °C to −19.5 °C, including the
GaryK [48]

Answer:

Explanation:

The heat required to change the temperature of  steam from 125.5  °C to 100 °C is:

Q_1 = ms_{steam} (125.5^0C - 100^0C) \\ \\ Q_1 = 0.175 \ kg ( 1520 \ J/kg.K ) (25.5^0 \ C) \\ \\ Q_1 = 6783 \ J

The heat required to change the steam at 100°C to water at 100°C is;

Q_2 = mL_v \\ \\ Q_2 = (0.175 \ kg) (2.25*10^6 \ J/kg ) \\ \\ Q_2 = 393750 \ J

The heat required to change the temperature from 100°C to 0°C is

Q_3 = ms_{water} (100^) \ C) \\ \\ Q_3 = (0.175\ kg)(4186 \ J/kg.K) (100 ^0c ) \\ \\ Q_3 = 73255 \ J

The heat required to change the water at 0°C to ice at 0°C  is:

Q_4 = mL_f \\ \\ Q_4 = (0.175 \ kg)(3.34*10^5 \ J/kg) \\\\ Q_4 = 58450 \ J

The heat required to change the temperature of ice from 0°Cto -19.5°C is:

Q_5 = ms _{ice} (100^0 C) \\ \\ Q_5 = (0.175 \ kg)(2090 \ J/kg.K)(19.5^0C)  \\ \\ Q_5 = 7132.125 \ J

The total heat required to change the steam into ice is:

Q = Q_1 + Q_2 + Q_3 + Q_4 +Q_5 \\ \\Q = (6788+393750+73255+58450+7132.125)J \\ \\ Q = 539325.125 \ J \\ \\ Q = 5.39*10^5 \ J

b)

The time taken to convert steam from 125 °C to 100°C is:

t_1 = \frac{Q_1}{P} = \frac{6738 \ J}{835 \ W}  = 8.12 \ s

The time taken to convert steam at  100°C to water at  100°C is:

t_2 = \frac{Q_2}{P} =\frac{393750}{834} =471.56 \ s

The time taken to convert water to 100° C to 0° C is:

t_3 = \frac{Q_3}{P} =\frac{73255}{834} = 87.73 \ s

The time taken to convert water at 0° to ice at 0° C is :

t_4 = \frac{Q_4}{P} =\frac{58450}{834} = 70.08  \ s

The time taken to convert ice from 0° C to -19.5° C is:

t_5 = \frac{Q_5}{P} =\frac{7132.125}{834} = 8.55  \ s

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The milky way is often considered to be an intermediately wound, barred spiral, which would be type ________ according to hubble
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SBb type spiral. Its a type B because its not too tightly wound but its still too tight to be a type C
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3 years ago
Rahul sits in a chair reading a book. Which force is equal to the force Rahul exerts on Earth?
Mademuasel [1]
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8 0
3 years ago
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The formula $F = \frac{9}{5} C + 32$ can be used to convert temperatures between degrees Fahrenheit ($F$) and degrees Celsius ($
slamgirl [31]

Answer:

-30° C

Explanation:

Data provided in the problem:

The formula for conversion as:

F  = (9/5)C + 32

Now,

for the values of F = -22 , C = ?

Substituting the value of F in the above formula, we get

-22 = (9/5)C + 32

or

-22 - 32 = (9/5)C

or

(9/5)C = - 54

or

C = - 54 × (5/9)

or

C = - 30 °

Hence, -22 Fahrenheit equals to -30°C

7 0
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