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Reil [10]
4 years ago
13

2. A jackscrew with a handle 30.0 cm long is used to lift a car sitting on the jack.

Engineering
1 answer:
myrzilka [38]4 years ago
3 0

Answer:

94.25

Explanation:

Given: Handle of jackscrew is 30 cm long. Also, the car raised 2.0 cm with every full turn of the handle.

To find: ideal  mechanical advantage of the jack

Solution:

Let d_e denotes the distance over which the effort is applied and d_r denotes the distance that the load travels.

Here,

d_r=2\,\,cm

d_e=2\pi(length\,\,of\,\,the\,\,handle)=2\pi(30)=60\pi

So,

Ideal  mechanical advantage of the jack\frac{d_e}{d_r}=\frac{60\pi}{2}=30\pi=30(\frac{22}{7})=94.25

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chubhunter [2.5K]

Answer:

#include <iostream>//including iostream library to use functions such as cout and cin

using namespace std;

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do

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If a machine uses LESS effort to overcome a given resistance force (if Fe is less than FR), it has an actual mechanical advantag
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