Question

2. A jackscrew with a handle 30.0 cm long is used to lift a car sitting on the jack.

Answer 1

Answer:

$94.25$

Explanation:

Given: Handle of jackscrew is 30 cm long. Also, the car raised 2.0 cm with every full turn of the handle.

To find: ideal  mechanical advantage of the jack

Solution:

Let $d_e$ denotes the distance over which the effort is applied and $d_r$ denotes the distance that the load travels.

Here,

$d_r=2\,\,cm$

$d_e=2\pi(length\,\,of\,\,the\,\,handle)=2\pi(30)=60\pi$

So,

Ideal  mechanical advantage of the jack$\frac{d_e}{d_r}=\frac{60\pi}{2}=30\pi=30(\frac{22}{7})=94.25$