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velikii [3]
3 years ago
15

List two industrial uses for nonmetallic mineral resources

Physics
1 answer:
Anni [7]3 years ago
4 0

Answer:

To make useful chemicals and abrasives

Explanation:

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A 45 g bug is hovering in the air. A gust of wind
MariettaO [177]

The work-done by the wind as the bug undergoes the displacement is 80 J.

The given parameters;

  • Mass of the bug, m = 45 g
  • Force exerted, F = (4.0 î – 6.0j) x 10⁻² N
  • Displacement of the bug, r = (8.0î - 8.0j) m

The work-done by the wind as the bug undergoes the displacement is obtained by finding the dot product of the force and the displacement;

Work done = F. r

Work done = (4.0 î – 6.0j) x 10⁻² . (8.0î - 8.0j)

Work done = (32i²) + (48j²)

Work done = 32(1) + 48(1)

Work done = 80 J.

Thus, the work-done by the wind as the bug undergoes the displacement is 80 J.

Learn more here:brainly.com/question/19498865

5 0
3 years ago
What happened 1 billion years after the Big Bang?
maks197457 [2]

Explanation:

1 billion years after the big bang, the temperature is 20K and some stars and galaxies began to contract due to the gravitational contraction of the over densities of the previous universe. At about 10 billion years after the big bang, our earth and sun form

8 0
4 years ago
Compared to a stationary galaxy, light from a galaxy that is moving away from earth will appear _____.
Vlad1618 [11]
"B" When an object moves away from us, the light is shifted to the red end of the spectrum, as its wavelengths get longer.
3 0
3 years ago
Read 2 more answers
Example of optical object​
Alik [6]

Answer:

Telescope,cameras

Hope it helped

5 0
3 years ago
Read 2 more answers
An object of mass m is dropped from height h above a planet of mass M and radius R.Find an expression for the object's speed as
Mnenie [13.5K]

Answer:

Explanation:

Mass of object = m

Height above planet = h

Mass of planet = M

Radius of planet = R

As we have to find out velocity, so let's apply the law of conservation of energies on initial( when the object was at height) and final( when object hit the surface points.

Initial energy = Final energy

K_{i} + U_{i} = K_{f} + U_{f}

\frac{1}{2}mv_{i} ^{2}  - \frac{GMm}{h+R} = \frac{1}{2}mv_{f} ^{2}  - \frac{GMm}{R}\\v_{i} = 0\\v_{f} ^{2} = 2\frac{GM}{R} - 2 \frac{GM}{h+R}

v_{f} =\sqrt{\frac{2GMh}{R(R+h)} }

4 0
4 years ago
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