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Ivenika [448]
3 years ago
14

Which part of the atom is not found in the nucleus? Is it proton, Neutron or Electron?

Physics
2 answers:
Vlad [161]3 years ago
7 0
The proton and the neutron are inside the nucleus and the electron is outside.
vovikov84 [41]3 years ago
5 0
It is Electron..
I hope this helps
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Answer:

true

Explanation:

or they will die to death

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HELP ME PLZ I HAVE LIMITED TIME Imagine your teacher asks you to design an experiment where you test the effect of temperature o
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Your variables would be varied temperature while your constants should be everything else (water, soil, proximity). Therefore, you can test for one variable (temperature difference) without muddling the results
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A billiard ball with a mass of 1.5kg is moving at 25m/s and strikes a second ball with a mass of 2.3 kg that is motionless. Find
aliya0001 [1]

Answer:

The velocity of the second ball after the collision will be 16.3 m/s.

Step-by-Step Explanation:

Law of conservation of momentum states that the total momentum of an isolated remains the same before and after the collision.

Let: mass of the first ball = m1 = 1.5 kg

mass of the second ball = m2 =  2.3 kg

Momentum before the collision:

velocity of the first ball = v1 = 25 m/s

velocity of the second ball = v2 = 0 m/s

[tex] Initial momentum = m1v1 + m2v2 = 1.5*25 + 2.3*0 = 37.5 kgm/s [\tex]

Momentum after the collision:

velocity of the first ball = v1 = 0 m/s

velocity of the second ball = v2 = x

[tex]momentum after the collision= m1v1 + m2v2 = 1.5*0 + 2.3*x = 2.3*x[\tex]

According to law of conservation of momentum:

Initial momentum = Momentum after collision

37.5 = 2.3*x

⇒ x = 37.5/2.3

x = 16.3 m/s

4 0
3 years ago
What are the stages of stellar evolution
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Giant Molecular Cloud


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3 0
4 years ago
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At a certain distance from the center of the Earth, a 0.4-kg object has a weight of 2.0 N. (a) Find this distance. (b) If the ob
Alika [10]

Answer:

a) The distance of the object from the center of the Earth is 8.92x10⁶ m.

b) The initial acceleration of the object is 5 m/s².

Explanation:

a) The distance can be found using the equation of gravitational force:

F = \frac{GMm}{r^{2}}

Where:

G: is the gravitational constant = 6.67x10⁻¹¹ Nm²/kg²

M: is the Earth's mass =  5.97x10²⁴ kg  

m: is the object's mass = 0.4 kg

F: is the force or the weight = 2.0 N    

r: is the distance =?

The distance is:

r = \sqrt{\frac{GMm}{F}} = \sqrt{\frac{6.67 \cdot 10^{-11} Nm^{2}/kg^{2}*5.97 \cdot 10^{24} kg*0.4 kg}{2.0 N}} = 8.92 \cdot 10^{6} m      

Hence, the distance of the object from the center of the Earth is 8.92x10⁶ m.

         

b) The initial acceleration of the object can be calculated knowing the weight:              

W = ma                                                  

Where:            

W: is the weight = 2 N

a: is the initial acceleration =?          

a = \frac{W}{m} = \frac{2 N}{0.4 kg} = 5 m/s^{2}

Therefore, the initial acceleration of the object is 5 m/s².

           

I hope it helps you!    

4 0
3 years ago
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