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Ivenika [448]
3 years ago
14

Which part of the atom is not found in the nucleus? Is it proton, Neutron or Electron?

Physics
2 answers:
Vlad [161]3 years ago
7 0
The proton and the neutron are inside the nucleus and the electron is outside.
vovikov84 [41]3 years ago
5 0
It is Electron..
I hope this helps
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Lever I believe when you pull up and down in the handels
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3 years ago
Ball is dropped from the height H the total distance covered in last second of its motion is equal to distance covered in first
Alik [6]

\rm{\gray{\underline{\underline{\blue{GIVEN:-}}}}}

  • A ball is dropped from a height = H

  • The total distance covered in last second of its motion is equal to the distance covered in first 3 second .

\rm{\gray{\underline{\underline{\blue{TO\:FIND:-}}}}}

  • The height of the journey .

\rm{\gray{\underline{\underline{\blue{SOLUTION:-}}}}}

We have know that,

\green\bigstar\:\rm{\gray{\overbrace{\underbrace{\red{S\:=\:ut\:+\:\dfrac{1}{2}\:at^2\:}}}}}

Where,

  • S = Distance .

  • u = initial velocity = 0m/s

  • t = time = 3s

  • a = acceleration

[Note :- Here, acceleration is ‛acceleration due to gravity’ .]

  • a = 10m/s^2

=> S = 1/2 × 10 × (3)^2

=> S = 5 × 9

=> S = <u>4</u><u>5</u><u>m</u> -----(1)

✒ If the ball takes ‛n’ second to fall the ground, then distance covered in nth second is,

\green\bigstar\:\rm{\gray{\overbrace{\underbrace{\red{S_n\:=\:u\:+\:\dfrac{g}{2}\:(2n\:-\:1)\:}}}}}

=> Sn = 0 + 10/2 (2 × n - 1)

=> Sn = 5 (2n - 1)

=> Sn = 10n - 5 -----(2)

Therefore,

  • 10n - 5 = 45

=> 10n = 45 + 5

=> n = 50/10

=> n = <u>5</u>

Now put the value of ‛n = 5’ in equation(2), we get

=> Sn = 10 × 5 - 5

=> Sn = 50 - 5

=> <u>Sn</u><u> </u><u>=</u><u> </u><u>4</u><u>5</u><u>m</u>

\rm{\pink{\therefore}} The height of the journey is “ <u>4</u><u>5</u><u>m</u> ” .

7 0
3 years ago
A student uses an electronic force sensor to study how much force the student’s finger can apply to a specific location. The stu
melisa1 [442]

Answer:

B. Trial 2

Explanation:

Trial 2, because the student’s finger applied the largest force to the sensor.

Because the trial 2 student finger applied to largest force.

7 0
3 years ago
Read 2 more answers
The amount of work done to bring an electron (q = −e) from right side of hydrogen nucleus to left side in the k shell is________
maksim [4K]

Answer:

d) 2Fr

Explanation:

We know that the work done in moving the charge from the right side to the left side in the k shell is W = ∫Fdr from r = +r to -r. F = force of attraction between nucleus and electron on k shell. F = qq'/4πε₀r² where q =charge on electron in k shell  -e and q' = charge on nucleus = +e. So, F = -e × +e/4πε₀r² = -e²/4πε₀r².

We now evaluate the integral from r = +r to -r

W = ∫Fdr

= ∫(-e²/4πε₀r²)dr

= -∫e²dr/4πε₀r²

= -e²/4πε₀∫dr/r²

= -e²/4πε₀ × -[1/r] from r = +r to -r

W = e²/4πε₀[1/-r - 1/+r] = e²/4πε₀[-2/r} = -2e²/4πε₀r.

Since F = -e²/4πε₀r², Fr = = -e²/4πε₀r² × r = = -e²/4πε₀r and 2Fr = -2e²/4πε₀r.

So W = -2e²/4πε₀r = 2Fr.

So, the amount of work done to bring an electron (q = −e) from right side of hydrogen nucleus to left side in the k shell is W = 2Fr

6 0
3 years ago
A 6 N and a 10 N force act on an object. The moment arm of the 6 N force is 0.2 m. If the 10 N force produces five times the tor
Levart [38]

Answer:

The moment arm is 0.6 m

Explanation:

Given that,

First force F_{1}=6\ N

Second force F_{2}=10\ N

Distance r = 0.2 m

We need to calculate the moment arm

Using formula of torque

\tau=Force\times lever\ arm

So, Here,

\tau_{2}=5 \tau_{1}

We know that,

The torque is the product of the force and distance.

Put the value of torque in the equation

F_{2}\times d_{2}=5\times F_{1}\times r_{1}

r_{2}=\dfrac{5\times F_{1}\times r_{1}}{F_{2}}

Where, F_{1}=First force

F_{1}=First force

F_{2}=Second force

r_{1}= distance

Put the value into the formula

r_{2}=\dfrac{5\times6\times0.2}{10}

r_{2}=0.6\ m

Hence, The moment arm is 0.6 m

6 0
3 years ago
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