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Semenov [28]
3 years ago
13

A truck is traveling due north at 75 km/hr approaching a crossroad. On a perpendicular road a police car is traveling west towar

d the intersection at 80 km/hr. Both vehicles will reach the crossroad in exactly one hour. Find the vector currently representing the displacement of the truck with respect to the police car.
Physics
1 answer:
Gre4nikov [31]3 years ago
7 0

Answer:

109.66km

Explanation:

Velocity is defined as the change in displacement of a body with respect to time.

Velocity = displacement/Time

Displacement = velocity * time

A truck is traveling due north at 75 km/hr approaching a crossroad and perpendicular road a police car is traveling west toward the intersection at 80 km/hr, then the resultant velocity is gotten using the pythagoras theorem since they are both perpendicular to each other.

v² = 75²+80²

v² = 5625+6400

v² = 12,025

v = √12,025

v = 109.66km/hr

If both vechicles reaches cross road in exactly one hour, the displacement of the truck with respect to the police car =  109.66km/hr * 1 hour

Displacement of the truck with respect to the police car = 109.66km

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3. A man heads up a trail going north to see a lake. The trail is 5 miles long and it takes him
scZoUnD [109]

Answer:

v = 2.5 mi/h

Explanation:

The velocity of an object is defined as the time rate of change of its position. In other words the velocity of an object is just a ration of displacement covered by the object to the time taken by the object, to cover that distance. So, in this case we will use the same formula or equation to calculate the velocity of the man. The formula is as follows:

v = s/t

where,

v = velocity of the man = ?

s = distance of the trail = 5 miles

t = time required to complete the trail = 2 h

Therefore,

v = 5 miles/ 2 h

<u>v = 2.5 mi/h</u>

7 0
3 years ago
The Andromeda Galaxy is faintly visible to the naked eye in the constellation Andromeda. Suppose instead it were located in the
Kaylis [27]

Answer:

a) We could not see it at all.

Explanation:

The most distant object that can be seen is the andromeda galaxy, which we may have a slight view of. The andromeda galaxy is a large galaxy that along with the previous two is also part of the local group. Spiral-type galaxy that is approximately 250,000 light years in diameter (more than twice the diameter of the Milky Way!) And is about 2.9 million light years away from our galaxy. Because of its distance, we have difficulty visualizing this galaxy, we would have this difficulty even if the andromeda galaxy was in the center of the Milky Way, but maintaining its current distance. That is, even if the andromeda galaxy were located in the same direction in space as the center of the Milky Way (but still at its current distance), we could not see it at all.

8 0
3 years ago
The speed of sound in water is 1,492 m/s. A sonar signal is sent straight down from a ship at a point just below the water's sur
ASHA 777 [7]

Answer:

5595 m

Explanation:

The wave travels down   (the depth) and the back up (the depth again)

  this distance is     2 d

2 d =  1492 m/s * 7.5 s

2d = 11190 m

d = 5595 m

6 0
2 years ago
There are four charges, each with a magnitude of 2.06 µC. Two are positive and two are negative. The charges are fixed to the co
mars1129 [50]

Answer:

0.208 N

Explanation:

We are given that

q_1=q_2=2.06\mu C=2.06\times 10^{-6} C

q_3=q_4=-2.06\mu C=-2.06\times 10^{-6} C

Distance,d=0.41 m

The magnitude of the net electrostatic force experienced by any charge at point 4

Net force,F_{net}=\sqrt{F^2_1+F^2_3+2F_1F_3cos90^{\circ}}-F_2

F_1=F_3=F

F_{net}=\sqrt{F^2+F^2+0}-F_2

F_{net}=\sqrt 2F-F_2

F=\frac{kq^2}{d^2}

F_2=\frac{Kq^2}{2d^2}

F_{net}=\frac{\sqrt 2kq^2}{d^2}-\frac{kq^2}{2d^2}=\frac{kq^2}{d^2}(\sqrt 2-\frac{1}{2})

Where k=9\times 10^9

F_{net}=\frac{9\times 10^9\times (2.06\times 10^{-6})^2}{(0.41)^2}(\sqrt 2-\frac{1}{2})

F_{net}=0.208 N

3 0
3 years ago
Does Mike wosowski blink or wink
aev [14]

Answer:

both

Explanation:

7 0
3 years ago
Read 2 more answers
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