Answer:
p = 20 kg•m/s
KE = 100 J
Explanation:
In an elastic collision of identical masses, the two masses will exchange momentums. Therefore Block 1 initially moving at 10 m/s will be moving at 2 m/s, and Block 2 will go from 2 m/s to 10 m/s
momentum = mv = 2(10) = 20 kg•m/s
KE = ½mv² = ½(2)10² = 100 J
Unfortunately, your answer selection does not have this answer as an option.
Answer:
22%
Explanation:
55 - 45 = 10
10/45 simplifies to 2/9
2/9 = 0.22222... so 22.22% (rounded 22%)
Answer: I didn't see a difference because the large ball's vertical displacement and velocity are the same as the small one's.
Explanation:
Answer:
Magnitude of net force will be 432.758 N
Explanation:
We have given x component of acceleration 
And vertical component of acceleration 
Mass of the ball m = 0.40 kg
So net acceleration 
Now according to second law of motion
Force = mass × acceleration
So F = 0.40×1081.896 = 432.758 N