Resistance can be calculated by Ohm's law
As per ohm's law we will have
here we will have
voltage = 220 volts
current = 10 A
So by the above formula we will have
So resistance of the bulb is 22 ohm.
A truck is traveling due north at 75 km/hr approaching a crossroad. On a perpendicular road a police car is traveling west towar
1 answer:
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Answer:
its potential energy decreases and its electric potential decreases.
Explanation:
Let's consider a radial field for simplicity. We have:
- The electric potential of the field is given by:
where
k is the Coulomb's constant
Q is the charge source of the field
r is the distance from Q
We see that the electric potential decreases as we move away from the source. If we consider a positive charge q moving in the direction of the electric field, this charge q will move away from the charge Q (because the field lines generated by the positive particle Q point away from the particle), so the electric potential will decrease.
- The potential energy of the moving charge is given by
where q is the magnitude of the charge. As we said previously, V is decreasing while the charge is moving in the direction of the field, so since U is directly proportional to V, U will decrease as well.
Answer:
Explanation:
The power delivered in the wire is given by:
where V is the voltage of the battery and R is the resistance of the wire.
Since the voltage of the battery is constant, we can rewrite this equation as follows:
(1)
At the beginning, the initial resistance is , and the power delivered is
. Later, when the temperature increases, the power becomes
, and the new resistance is
. Using (1), we can write
(2)
So, the new resistance must be 3/2 of the initial resistance.
We know that the resistance increases linearly with the temperature, as
where
is the temperature coefficient
is the change in temperature
Using (2), we can rewrite this equation as
and we find:
So, the new temperature of the wire must be